Question

如何在一段时间后停止执行该方法？我打电话的方法如下：

    def make_decimal_to_n_ary_converter(n):
    def converter(x):
        if x==0 or x==1:   
            return x
        i=x
        b=('A','B','C','D','E','F')
        result = ""
        while i>0:
            a=i%n          #3
            if a<10:
                result = str(i%n)+result
            else:
                d=a-10
                result = b[d] + result
            i=i//n

        return result
    return converter

#Lines below are not to be changed, part of qn
decimal_to_binary = make_decimal_to_n_ary_converter(2)
decimal_to_octal = make_decimal_to_n_ary_converter(8)
decimal_to_hexadecimal = make_decimal_to_n_ary_converter(16)

这里我给出了5秒的间隔。因此，此方法将在每5秒后调用一次，因此一旦到达指定时间，我想停止此方法执行。

Answer 1

取一个计数器变量，每次调用增加5（如时间间隔为5秒），如

counter = counter+5;

    -(void) doSomeTask {

     if (counter<=60) {  // 5 min = 300   300/5 = 60

       // Write method body here

         counter = counter+5 
      }

       else {
          [timer invalidate];
       }
    }

Answer 2

如果你想在5分钟后停止通话。然后这样做

 @interface YourClass () {
        int count;
    }

 @end
  - (void)viewDidLoad {
        count = 5;
        NSTimer *timer = [NSTimer scheduledTimerWithTimeInterval:5.0f
                                    target:self
                                   selector:@selector(doSomeTask) userInfo:nil repeats:YES];

  }
  -(void) doSomeTask
  {
             count = count + 5;
             if (count==300)
             {
                 [timer invalidate];
                 timer=nil;
             }
  }

Answer 3

你可以这样尝试

NSTimer *reachTimer;
NSInteger secondsLeft;

- (void)viewDidLoad {
    [super viewDidLoad];
    // Do any additional setup after loading the view.
    secondsLeft = 0;

reachTimer = [NSTimer scheduledTimerWithTimeInterval:5.0f target:self selector:@selector(updateCounter:) userInfo:nil repeats:YES];

}

-(void)updateCounter:(NSTimer *)theTimer{
 secondsLeft = secondsLeft+5;

 if(secondsLeft>=300) // 60sec * 5min= 300 
 {
    [reachTimer invalidate];
 }

}

Answer 4

#define TIMER_LIFE_IN_SECONDS 300.0
@interface YourClass () {
    NSTimeInterval _startTime;
}

self.timer = [NSTimer scheduledTimerWithTimeInterval:5.0f target:self selector:@selector(doSomeTask) userInfo:nil repeats:YES];
_startTime = [NSDate timeIntervalSinceReferenceDate];


- (void) doSomeTask
{
    // do thing

    NSTimeInterval now = [NSDate timeIntervalSinceReferenceDate];
    if (now - _startTime > TIMER_LIFE_IN_SECONDS) {
        [self.timer invalidate];
        self.timer = nil;
    }
}

Answer 5

试试这个;

int count;
NSTimer *timer;

-(void)startTimertillLimit:(int)limit {
     count = 0;
     timer = [NSTimer scheduledTimerWithTimeInterval:5
                                              target:self
                                            selector:@selector(doSomething:)
                                            userInfo:[NSString stringWithFormat:@"%d",limit]
                                             repeats:YES];
}

-(void)doSomething:(NSTimer*)sender
{
     int limit = (int)[sender.userInfo intValue];
     count = count + 5;
     if (count > limit)
     {
         [timer invalidate];
         timer=nil;
         count = 0;
     }
}

Answer 6

尝试创建仅在一段时间后调用的NSTimer：

NSTimer *previous [NSTimer scheduledTimerWithTimeInterval:5.0f target:self selector:@selector(doSomeTask) userInfo:nil repeats:YES];

[NSTimer scheduledTimerWithTimeInterval:300 target:self selector:@selector(stopPrevious) userInfo:nil repeats:NO];

-(void)stopPrevious{
    [previous invalidate];
}

5分钟后停止方法执行

6 个答案: