我有一个Android应用程序，用于为每个User插入用户记录。每个用户每天只能将数据输入数据库2次。如果用户第三次尝试输入数据（单击“提交”按钮），将显示一个带有消息的新活动（在Android中），并且日期字段（TextView）应该增加1天。我能够添加每次点击，日期字段为1天。所以我试过的是在特定日期获取每个用户的MYSQL数据库中的数据计数，如果计数大于3，则PHP脚本将返回一个echo语句，根据该语句，Anroid中的异步任务将功能并显示新的活动。
我的PHP脚本是：
<?php
require "conn.php";
require "SalesLogin.php";
$enquiry = $_POST["enquiry"];
$retail = $_POST["retail"];
$collection = $_POST["collection"];
$booking = $_POST["booking"];
$evaluation = $_POST["evaluation"];
$test_drive = $_POST["test_drive"];
$home_visit = $_POST["home_visit"];
$user_name = $_POST["user_name"];
$update_date = $_POST["date"];
$absent = $_POST["absent"];
$timezone = new DateTimeZone("Asia/Kolkata" );
$date = new DateTime();
$date->setTimezone($timezone );
$time = $date->format( 'H:i:s A' );
$sql = "UPDATE employee_details SET
enquiry_sum = (SELECT SUM(enquiry) +'$enquiry' FROM (SELECT * FROM employee_details WHERE date = CURDATE() AND name = '$user_name') AS x)
WHERE date = CURDATE() AND name = '$user_name'";
$res = $conn->query($sql);
$check = "UPDATE employee_details SET enquiry_target_status = ( SELECT IF (MAX(enquiry_sum) = 52, 'ACHIEVED', 'NOT ACHIEVED') FROM (SELECT * from employee_details WHERE date = CURDATE() AND name = '$user_name') AS Y ) WHERE date = CURDATE() AND name = '$user_name'";
$insert_status = $conn->query($check);
$miss_count = "UPDATE employee_details SET enquiry_target_missed_by = (SELECT (50 - MAX(enquiry_sum)) FROM (SELECT * from employee_details WHERE date = CURDATE() AND name = '$user_name') AS Z ) WHERE date = CURDATE() AND name = '$user_name'";
$insert_status = $conn->query($miss_count);
$mysql_qry1 = "INSERT INTO employee_details(enquiry,retail,
collection,booking, evaluation, test_drive, home_visit, name, date,time,absent) values ('$enquiry','$retail','$collection','$booking','$evaluation','$test_drive',
'$home_visit','$user_name','$update_date','$time','$absent');";
if($conn->query($mysql_qry1) === TRUE)
echo "Your details has been successfully inserted.";
else
echo "Error: " .$mysql_qry1. "<br>" . $conn->error;
if($update_date != $date){
$mysql_qry2 = "UPDATE employee_data SET last_updated_date = (DATE_ADD('$update_date', INTERVAL 1 DAY)) WHERE name = '$user_name';";
$conn->query($mysql_qry2);
echo "Date changed," .$mysql_qry2;
}
$mysql_qry3 = "SELECT COUNT(*) from employee_details WHERE date = '$update_date' and name LIKE '$user_name';";
$conn->query($mysql_qry3);
if($mysl_qry3 <= 2)
{
echo "You can login.";
}
else
{
echo "You cannot login anymore for today.";
}
$conn->close();
?>
我的AsyncTask代码是：
@Override
protected void onPostExecute(String result) {
try {
if (result.contains("Welcome") && result.contains("Date")) {
String[] str = result.split("_");
String name = str[1];
String[] date = result.split(":");
String upd_date = date[1];
Intent intent = new Intent(context,InsertDataActivity.class);
intent.putExtra("username",name);
intent.putExtra("date",upd_date);
context.startActivity(intent);
}
else if (result.contains("Login failed.") && !(result.contains("Undefined")))
Toast.makeText(context,"Invalid Crendentials.",Toast.LENGTH_LONG).show();
else if (result.contains("You cannot login anymore for today.")) {
Log.i("Check",result);
Intent intent = new Intent(context,ThankYouActivity.class);
context.startActivity(intent);
}
} catch (NullPointerException e) {
Toast.makeText(context,"No Internet Connectivity found.Please connect to the internet first and then retry.",Toast.LENGTH_LONG).show();
}
}
但是我的代码工作不正常。有人可以帮我这个吗？
答案 0 :(得分：0)
我使用下面的PHP脚本解决了这个问题。我没有为使用“AS”完成的SQL输出使用别名。下面的脚本工作正常，并提供了所需的结果。
<?php
require "conn.php";
require "SalesLogin.php";
$enquiry = $_POST["enquiry"];
$retail = $_POST["retail"];
$collection = $_POST["collection"];
$booking = $_POST["booking"];
$evaluation = $_POST["evaluation"];
$test_drive = $_POST["test_drive"];
$home_visit = $_POST["home_visit"];
$user_name = $_POST["user_name"];
$update_date = $_POST["date"];
$absent = $_POST["absent"];
$timezone = new DateTimeZone("Asia/Kolkata" );
$date = new DateTime();
$date->setTimezone($timezone );
$time = $date->format( 'H:i:s A' );
$sql = "UPDATE employee_details SET
enquiry_sum = (SELECT SUM(enquiry) +'$enquiry' FROM (SELECT * FROM employee_details WHERE date = CURDATE() AND name = '$user_name') AS x)
WHERE date = CURDATE() AND name = '$user_name'";
$res = $conn->query($sql);
$check = "UPDATE employee_details SET enquiry_target_status = ( SELECT IF (MAX(enquiry_sum) = 52, 'ACHIEVED', 'NOT ACHIEVED') FROM (SELECT * from employee_details WHERE date = CURDATE() AND name = '$user_name') AS Y ) WHERE date = CURDATE() AND name = '$user_name'";
$insert_status = $conn->query($check);
$miss_count = "UPDATE employee_details SET enquiry_target_missed_by = (SELECT (50 - MAX(enquiry_sum)) FROM (SELECT * from employee_details WHERE date = CURDATE() AND name = '$user_name') AS Z ) WHERE date = CURDATE() AND name = '$user_name'";
$insert_status = $conn->query($miss_count);
$mysql_qry1 = "INSERT INTO employee_details(enquiry,retail,
collection,booking, evaluation, test_drive, home_visit, name, date,time,absent) values ('$enquiry','$retail','$collection','$booking','$evaluation','$test_drive',
'$home_visit','$user_name','$update_date','$time','$absent');";
if($conn->query($mysql_qry1) === TRUE)
echo "Your details has been successfully inserted.";
else
echo "Error: " .$mysql_qry1. "<br>" . $conn->error;
if($update_date != $date){
$mysql_qry2 = "UPDATE employee_data SET last_updated_date = (DATE_ADD('$update_date', INTERVAL 1 DAY)) WHERE name = '$user_name';";
$conn->query($mysql_qry2);
echo "Date changed," .$mysql_qry2;
}
$mysql_qry3 = "SELECT COUNT(*) AS count from employee_details WHERE date = '$update_date' and name LIKE '$user_name';";
$result1 = mysqli_query($conn,$mysql_qry3);
$row = mysqli_fetch_assoc($result1);
$count = $row['count'];
echo "Count: " .$count;
if($count <= 2)
{
echo "You can login.";
}
else
{
echo "You cannot login anymore for today.";
}
$conn->close();
?>