Question

我正在尝试使用＆＃34; GET＆＃34;

从PHP服务器向Java服务器发送输入

我发送的请求没有问题 Request and Response

服务器都已连接，我收到回复＆＃34; null请输入一个号码＆＃34;

其中null是

的输出

out.println(inputdata);

我的代码

HTML

<html>
<head>
<meta charset="UTF-8">
<title>Cloud Computing</title>

</head>
<body>
<form action="url.php" method="get">
Input: <input type="text" name="inputdata" ><br>
       <input align="center" type="submit">
</form>

</body>
</html>

PHP

<html>
 <head>
 <meta charset="UTF-8">
  <title>PHP Test</title>
 </head>
 <body>
 <form action="url.php" method="get">
Input: <input type="text" name="inputdata" ><br>
<input align="center" type="submit">
</form>
<font face="century gothic" size="20px">
    <center> </br></br>
    <?php 

        echo "Query for:";
        echo $_GET["inputdata"]; 
        //echo $_POST["inputdata"];
         $inputdata = $_GET["inputdata"]; 
         $url = "http://localhost:8080/CloudComputingProj/Cloudpi";

    $post_params_s = ["inputdata"=>$inputdata];

    $curl = curl_init();
    curl_setopt($curl, CURLOPT_URL, $url);
    curl_setopt ( $ch, CURLOPT_POST          , TRUE ) ;
    curl_setopt ( $ch, CURLOPT_POSTFIELDS    , $post_params_s ) ;
    curl_setopt ( $ch, CURLOPT_RETURNTRANSFER, TRUE ) ; 
    curl_exec($curl);
    curl_close($curl);
?></center>
</font>

 </body>
</html>

Java Server

protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            // TODO Auto-generated method stub
            System.out.println("Inside Service");

            System.out.println(request.getQueryString());
            if(request.getMethod().equals("GET")){
                doGet(request, response);
            }
        }
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            // TODO Auto-generated method stub
           //   System.out.println(request.getParameterMap());     //Returns null
            InputStream requestBodyInput = request.getInputStream();
            String inputdata = request.getParameter("inputdata");
            System.out.println(inputdata);
            //response.getWriter().append(" \n Served at: ").append(request.getContextPath());
            response.setContentType("text/html");
             PrintWriter out = response.getWriter();
             //out.println("Hello World!");
             out.println(inputdata);
            // System.out.println(request.getQueryString());
             if (request.getParameter("inputdata") == null) {
                 out.println("Please enter a number");
             } else {
                 out.println("Hello <b>"+request. getParameter("input")+"</b>!");
             }

        }

我在这里找不到任何内容＆＃34; 请求＆＃34;，没有任何标准方法可以提供除<＆lt; null ＆＃39;请帮忙！我是新手。

Answer 1

您正在检查不存在的输入

if (request.getParameter("input") == null)
                          ^^^^^

我认为应该如下：

if (request.getParameter("inputdata") == null)

更新

当您检查curl请求类型时，您是将请求发布到GET。

if(request.getMethod().equals("GET"))

您需要检查请求是否已发布，然后get the POST request body或将curl设置为发送带有简单查询字符串的GET请求。

Answer 2

尝试将php代码修改为$url = "http://localhost:8080/CloudComputingProj/Cloudpi?inputdata=".$inputdata 您还可以通过在任何浏览器http://localhost:8080/CloudComputingProj/Cloudpi?inputdata=your-encoded-param

中键入get请求来调试java端

java服务器中的请求没有查询字符串

2 个答案:

更新