Question

我知道有几个帖子已经提出了这个问题，我尝试了一些解决方案，但我仍然收到错误消息。以下两种解决方案都会产生相同的错误消息。我做错了什么？

这是我尝试过的一个解决方案：

def main():
    #Open a file named numbers.txt
    numbers_file = open('numbers.txt','r')

    #read the numbers on the file
    file_contents = numbers_file.read()

    #Close the the numbers file
    numbers_file.close()

    #Print the data that was inside the file
    print(numbers_file)

#Call the main function
main()

这是我尝试的另一个解决方案：

with open(r"numbers.txt",'r') as numbers_file:
    #read the numbers on the file
    file_contents = numbers_file.read()

    #Close the the numbers file
    numbers_file.close()

    #Print the data that was inside the file
    print(numbers_file)

运行任一程序时收到的错误消息是：

<_io.TextIOWrapper name='numbers.txt' mode='r' encoding='cp1252'>

Answer 1

感谢您的帮助。我意识到我做错了什么。这是我得到的：

def main():
    #Open a file named numbers.txt
    numbers_file = open('numbers.txt','r')

    #read the numbers on the file
    file_contents = numbers_file.read()

    #Close the the numbers file
    numbers_file.close()

    #Print the data that was inside the file
    print(file_contents)

#Call the main function
main()

如何修复Python io.TextIOWrapper错误消息？

1 个答案: