如何关闭dart2js生成的代码中的类型检查?

时间:2017-03-10 05:42:22

标签: dart

我正在为简单的矩阵运算编写库。例如:要乘以转置矩阵,我有一个如下所示的方法:

Matrix multTransp(Matrix m2) {
    Matrix res = new Matrix(rows, m2.rows);
    for (int r = 0; r < rows; r++) {
        for (int c = 0; c < m2.rows; c++) {
            double sum = 0.0;
            for (int i = 0; i < cols; i++) {
                sum += get(r, i) * m2.get(c, i);
            }
            res.set(r, c, sum);
        }
    }
    return res;
}

dart2js(带checked: false)生成带有类型和范围检查的代码:

  multTransp$1: function(m2) {
    var t1, t2, res, t3, t4, t5, t6, t7, t8, r, t9, t10, c, sum, i, t11, t12;
    t1 = this.rows;
    t2 = m2.rows;
    res = L.Matrix$(t1, t2);
    for (t3 = res.m, t4 = res.rows, t5 = t3.length, t6 = this.cols, t7 = this.m, t8 = t7.length, r = 0; r < t1; ++r)
      for (t9 = m2.m, t10 = t9.length, c = 0; c < t2; ++c) {
        for (sum = 0, i = 0; i < t6; ++i) {
          t11 = r + i * t1;
          if (t11 < 0 || t11 >= t8)
            return H.ioore(t7, t11);
          t11 = t7[t11];
          t12 = c + i * t2;
          if (t12 < 0 || t12 >= t10)
            return H.ioore(t9, t12);
          t12 = J.$mul$ns(t11, t9[t12]);
          if (typeof t12 !== "number")
            return H.iae(t12);
          sum += t12;
        }
        t11 = r + c * t4;
        if (t11 < 0 || t11 >= t5)
          return H.ioore(t3, t11);
        t3[t11] = sum;
      }
    return res;
  }

如何关闭所有这些支票?这些for循环中的代码似乎是我的应用程序的性能瓶颈,所以这里的任何优化对我来说都是一个很大的胜利。

0 个答案:

没有答案