Question

我正在尝试将模式从一个MYSQL数据库复制到其他MYSQL数据库。虽然这样做的表很少，但问题如下

let result = processString({
    regex: /[0-9+]/gim,
    fn: (key, match) => <span key={key}>{match[1]}</span>
})(mask);

MYSQL SCRIPT

Error Code: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(6) DEFAULT NULL,
  `is_superuser` tinyint(1) NOT NULL,
  `username` varchar(30)' at line 4

Execution Time : 0 sec
Transfer Time  : 0 sec
Total Time     : 0 sec

Answer 1

将DATETIME更改为TIMESTAMP：

像这样：

CREATE TABLE `auth_user` (
  `id` INT(11) NOT NULL AUTO_INCREMENT,
  `password` VARCHAR(128) NOT NULL,
  `last_login` TIMESTAMP NOT NULL,
  `is_superuser` TINYINT(1) NOT NULL,
  `username` VARCHAR(30) NOT NULL,
  `first_name` VARCHAR(30) NOT NULL,
  `last_name` VARCHAR(30) NOT NULL,
  `email` VARCHAR(254) NOT NULL,
  `is_staff` TINYINT(1) NOT NULL,
  `is_active` TINYINT(1) NOT NULL,
  `date_joined` TIMESTAMP NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `username` (`username`)
) ENGINE=INNODB AUTO_INCREMENT=33 DEFAULT CHARSET=latin1;

Answer 2

MySQL以'YYYY-MM-DD HH：MM：SS'格式检索并显示DATETIME值。支持的范围是'1000-01-01 00:00:00'到'9999-12-31 23：59：59'。您不需要指定datetime数据类型的长度

DROP TABLE IF EXISTS `auth_user`;

CREATE TABLE `auth_user` (
  `id` INT(11) NOT NULL AUTO_INCREMENT,
  `password` VARCHAR(128) NOT NULL,
  `last_login` DATETIME DEFAULT NULL,
  `is_superuser` TINYINT(1) NOT NULL,
  `username` VARCHAR(30) NOT NULL,
  `first_name` VARCHAR(30) NOT NULL,
  `last_name` VARCHAR(30) NOT NULL,
  `email` VARCHAR(254) NOT NULL,
  `is_staff` TINYINT(1) NOT NULL,
  `is_active` TINYINT(1) NOT NULL,
  `date_joined` DATETIME NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `username` (`username`)
) ENGINE=INNODB AUTO_INCREMENT=33 DEFAULT CHARSET=latin1;

MYSQL：为什么我无法创建表

2 个答案: