Question

我希望获得＆＃34;名称＆＃34;和＆＃34;尺寸＆＃34;用户键入搜索框的值。

但显而易见的问题是，我试图从method: "POST" hmtl表单获取值。我的html操作只引用了{{ url_for('main') }} html，而不想在{{url_for（＆＃39; search＆＃39;）}} html中检索这些值。

以下是模板：

import sqlite3
from flask import Flask,render_template, url_for, redirect, request


app = Flask(__name__)
conn = sqlite3.connect('shoes.db', check_same_thread=False)
c = conn.cursor()

@app.route("/", methods=["GET", "POST"])
def main():

    if request.method == 'GET':
        return render_template('main.html')

    elif request.method == 'POST':
        name = request.form.get('name')
        size = request.form.get('size')
        return redirect(url_for('search'))


@app.route("/search/", methods=["GET", "POST"])
def search():

    # Need to get the 'name' and 'search' values from input, so this way is incorrect.
    name = request.args.get("name") 
    size = request.args.get("size")     

    c.execute("SELECT * FROM shoes WHERE name LIKE ? AND sizes LIKE ? ORDER BY price",
                    ('%'+name+'%','%'+size+'%'))

    p = c.fetchall()

    url = [p[i][0] for i in range(len(p))]
    names = [p[i][1] for i in range(len(p))]
    prices = [p[i][2] for i in range(len(p))]
    sizes = [p[i][3] for i in range(len(p))]
    shoe_type = [p[i][4] for i in range(len(p))]

    return render_template('search.html' , url=url, names=names, prices=prices,
                           sizes=sizes, shoe_type=shoe_type)


if __name__ == '__main__':
    app.run(debug=True)

main.html中：

{% extends "layout.html" %}
{% block content %}

<form action = "{{ url_for('main') }}" class="form" method = "POST" >

        <h1>Soccer Shoes Finder</h1>
        <div class="line-separator"></div>

            <div class="container-fluid">
                <input name = "name" type="text" placeholder="Name"/>
                <input name = "size" type="text" placeholder="Size"/>
                <button class="glyphicon glyphicon-search" aria-hidden="true"></button>
            </div>

</form>

{% endblock %}

search.html：

{% extends "layout.html" %}
{% block content %}


    <div class= "container">
    <h2>Results:</h2>
    <table class="table table-striped">
    <thead>
    <tr>
        <th>url</th>
        <th>Name</th>
        <th>Prices</th>
        <th>Sizes</th>
        <th>Shoe Type</th>
    </tr>
    </thead>
    <tbody>
    {% for i in range(url|length) %}
    <tr>
        <td><a href={{url[i]}}>aa</td>
        <td>{{names[i]}}</td>
        <td>${{prices[i]}}</td>
        <td>{{sizes[i]}}</td>
        <td>{{shoe_type[i]}}</td>
    </tr>
    {% endfor %}
    </tbody>
    </table>
    </div>
{% endblock %}

任何人都知道如何实现这一目标？希望我所说的是有道理的。感谢。

Answer 1

简化您的主要路线，似乎没有理由在此处发布数据：

@app.route("/")
def main():
    return render_template('main.html')

通过在 main.html Jinja模板中更改此行，

POST将数据直接发送到搜索端点：

<form action="{{ url_for('search') }}" class="form" method="POST">

由于此页面呈现取决于具有表单数据，我只是将其设置为仅接受POST方法，但这取决于您。您需要使用request.form （或request.values，如果您还想支持查询字符串GET方法）来访问此处的值。

@app.route("/search/", methods=["POST"])
def search():
    name = request.form.get("name") 
    size = request.form.get("size")

假设您的数据库代码正常工作，其余部分应按预期工作

烧瓶 - 获取价值

1 个答案: