Question

我的目标是......

如果日期已过期...脚本会再向用户提供1天，如果未订阅，则会删除用户数据。

我怎么能这样做？......我尝试过INTERVAL 1天，但是......我不知道是否有效......

// Check Expire Dates and Delete Expired 1 day after.
  $now = date('Y-m-d');

  if ($row['expire_admin'] > $now)
  {
    echo " <a href='#' id='profileGhost'> ". $row['expire_admin'] . "</a>";
  }
  else
  {
    echo " <a href='#' id='profileGhost'>Expired.</a>";
    $queryExpire = "DELETE FROM public_vips WHERE expire_admin(expire_admin, INTERVAL 1 day), steamid='$steamID'";
    $expiredQ = mysqli_query($db, $queryExpire);
  }

Answer 1

您的SQL应该是

DELETE FROM public_vips 
WHERE expire_admin(expire_admin, INTERVAL 1 day)
    AND steamid='$steamID'

Answer 2

// Check Expire Dates and Delete Expired 1 day after.
$now = new DateTime();
$tomorrow = new DateTime();
$tomorrow->add( new DateInterval( 'P1D' ) );
$expiration_date = DateTime::createFromFormat('Y-m-d', $row['expire_admin'] );

if ( $expiration_date->format('u') > $now->format('u') )
{
    if( $expiration_date->format('u') < $tomorrow->format('u') )
        echo " <a href='#' id='profileGhost'> ". $row['expire_admin'] . "</a>";
    }
    else
    {
        echo " <a href='#' id='profileGhost'>Expired.</a>";

        // I suppose that steamID is the unique id of the row you are currently check
        $queryExpire = "DELETE FROM public_vips WHERE steamid='$steamID'";
        $expiredQ = mysqli_query($db, $queryExpire);
    }
}

php检查过期日期并在1天后删除

2 个答案: