蛮力脚本

Question

我正在创建一个简单的暴力脚本，但我似乎无法弄明白。我正在使用this question中接受的答案，但我无法“尝试”等于用户密码。下面是我使用的代码（来自链接的问题），并稍微改了一下。

from string import printable
from itertools import product

user_password = 'hi' # just a test password
for length in range(1, 10): # it isn't reasonable to try a password more than this length
    password_to_attempt = product(printable, repeat=length)
    for attempt in password_to_attempt:
        if attempt == user_password:
            print("Your password is: " + attempt)

我的代码只运行直到它到达笛卡尔结尾，并且从不打印最终答案。不知道发生了什么。

任何帮助将不胜感激！

Answer 1

itertools.product()为您提供元组的集合，而不是字符串。因此，您最终可能会得到结果('h', 'i')，但这与'hi'不同。

您需要将字母组合成一个字符串进行比较。此外，您应该在找到密码后停止该程序。

from string import printable
from itertools import product

user_password = 'hi' # just a test password
found = False

for length in range(1, 10): # it isn't reasonable to try a password more than this length
    password_to_attempt = product(printable, repeat=length)

    for attempt in password_to_attempt:
        attempt = ''.join(attempt) # <- Join letters together

        if attempt == user_password:
            print("Your password is: " + attempt)
            found = True
            break

    if found:
        break

Try it online!