Question

所以有什么方法可以让python告诉我每当我打开文件？

所以，如果我打开file.txt它会告诉我，我打开它打开了＃34;你打开了file.txt＆＃34;或者某种东西，它会用我打开的任何文件来做到这一点。

示例：

file = any files in the entire OS
if file == open:
    print("you opened:", file)

所以，如果我打开Skype，那就是：

"you opened: Skype.exe"

如您所见，我显然不知道该怎么做。

我正在使用python 3.4和Windows 8.1。

告诉我是否有任何需要澄清的内容。

Answer 1

这应该有效：

import wmi
import time
c = wmi.WMI ()

def check_process():
    for process in c.Win32_Process ():
        L = []
        L.append(process.Name)

while True:
    check_process()
    L2 = L[:]
    time.sleep(1) # check every second
    check_process()
    if set(L2) & set(L) != set():
        print ('you opened:',process.Name)

阅读List running processes on 64-bit Windows

Answer 2

这很有用。

import wmi
import time
c = wmi.WMI ()



while True:

    for process in c.Win32_Process ():

        proccesses = process.Name
    time.sleep(1)

    file = open("proccesses.txt", 'w')
    file.write("%s" % (proccesses))
    file.close()

    file = open("proccesses.txt", "r")
    lastProccess = [line.split(',') for line in file.readlines()]
    print(lastProccess[-1])

当我打开文件时，如何让python告诉我？

2 个答案: