Question

当我使用laravel分页时，我得到一个这样的对象：

{
    "per_page": 1000,
    "current_page": 2,
    "next_page_url": null,
    "prev_page_url": null,
    "from": null,
    "to": null,
    "data": []
}

我想在该对象中添加＆＃39;过滤器＆＃39;我的控制器中的属性，以便在响应中返回已添加的过滤器。像这样：

{
    "per_page": 1000,
    "current_page": 2,
    "next_page_url": null,
    "prev_page_url": null,
    "from": null,
    "to": null,
    "data": [],
    "filters" : []
}

当我尝试在我的控制器中执行此操作时，例如

$paginated->filters = [ ];

它没有效果，响应对象保持不变。

有什么想法吗？

提前致谢

Answer 1

您可以使用namespace restaurant{ attribute userId{ category = subjectCat id = "restaurant.userId" type = string } attribute owner{ category = resourceCat id = "restaurant.resourceCat" type = string } policy restaurant{ target clause objectType == "restaurant" apply firstApplicable rule ownerCanView{ target clause actionId == "view" permit condition userId == restaurant.owner } } }获取响应数组。然后你可以随心所欲地修改它。

present(viewControllerToPresent: yourVC , animated: true, completion:nil)

更改laravel分页响应对象

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