我在php中编写了一个简单的MongoDB查询
计算过去一小时的在线总数 一切正常
但我觉得这种方式不利于表现
因为查询它自我返回所有匹配数据(因此该查询中有不需要的数据)
我需要的只是记录数
我有一个拥有数百万份文件的集合
脚本:
<?php
// Last Online Time
$Time = time() - 86400;
// Connection
$Manager = new MongoDB\Driver\Manager("mongodb://" . DB_USERNAME . ":" . DB_PASSWORD . "@" . DB_HOST . ":" . DB_PORT . "/" . DB_NAME);
// Query
$Query = new MongoDB\Driver\Query(['LastOnlineTime' => ['$gt' => (int) $Time]], []);
// Result
$Result = $Manager->executeQuery(DB_NAME . "." . $Collection, $Query);
// Get Total Online In 1 Hour Ago
echo count($Result->toArray());
?>
我的感觉权利吗?
答案 0 :(得分:3)
我找到了一个更好的解决方案MongoDB Command
这是
<?php
// Last Online Time
$Time = time() - 86400;
// Connection
$Manager = new MongoDB\Driver\Manager("mongodb://" . DB_USERNAME . ":" . DB_PASSWORD . "@" . DB_HOST . ":" . DB_PORT . "/" . DB_NAME);
// Command
$Command = new MongoDB\Driver\Command(["count" => "account", "query" => ['LastOnline' => ['$gt' => (int) $Time]]]);
// Result
$Result = $Manager->executeCommand(DB_NAME, $Command);
//print($Result->toArray());Array ( [0] => stdClass Object ( [n] => 228598 [ok] => 1 ) //so n is our totalcount
// Get Total Online In 1 Hour Ago
echo count($Result->toArray()[0]->n);
&GT;