Question

我有这个表DDL：

CREATE TABLE [dbo].[Audit] (
    [AuditId] INT              IDENTITY (1, 1) NOT NULL,
    [Entity]  INT              NOT NULL,
    [Action]  INT              NOT NULL,
    [Id]      UNIQUEIDENTIFIER NULL,
    CONSTRAINT [PK_Audit] PRIMARY KEY CLUSTERED ([AuditId] ASC)
);

更新 - 我在这里添加了缺少的SQL。抱歉，

我所做的是使用这个SQL创建一个SQL报告，它会告诉我每天有多少活动：

select [col1] = CONVERT(VARCHAR(10), DATEADD(HOUR, 8, a.date), 101) ,
       [Col2] = convert(varchar, count(*))
from Audit a
group by CONVERT(VARCHAR(10), DATEADD(HOUR, 8, a.date), 101)
order by CONVERT(VARCHAR(10), DATEADD(HOUR, 8, a.date), 101) desc

输出如下：

col1        Col2
03/05/2017  1
03/04/2017  20
03/03/2017  10
03/02/2017  5
03/01/2017  10

我现在需要做的是创建一个SQL选择，它显示累积值而不是计数。所以我需要SQL来创建一个显示这个

的报告

col1        Col2
03/05/2017  46
03/04/2017  45
03/03/2017  25
03/02/2017  15
03/01/2017  10

有没有人知道如何修改我的SQL以创建这种类型的报告？

请注意，我正在寻找一个命令解决方案，因为它是从.net框架执行的，如果解决方案中有多个命令，我想我需要弄清楚如何以某种方式将它放入存储过程。

Answer 1

您可以使用窗口函数Sum() Over

Select col1 = convert(varchar(10),cast(dateadd(HOUR, 8, a.date) as date),101)
      ,col2 = sum(count(*))  over (Order by cast(dateadd(HOUR, 8, a.date) as date))
 From  Audit a
 Group by cast(dateadd(HOUR, 8, a.date) as date)
 Order By cast(dateadd(HOUR, 8, a.date) as date) Desc

返回

col1        Col2
03/05/2017  46
03/04/2017  45
03/03/2017  25
03/02/2017  15
03/01/2017  10

Answer 2

使用“with”语句将总和包含在一个命令中。像这样：

WITH TBL ([col1], [col2])  
AS  
(  
SELECT [col1] = CONVERT(DATE, DATEADD(HOUR, 8, a.date)),
       [Col2] = COUNT(*)
FROM Audit a
GROUP BY CONVERT(DATE, DATEADD(HOUR, 8, a.date))
)  
SELECT  [col1] = CONVERT(VARCHAR(10), t1.[col1], 101), 
        [col2] = CONVERT(VARCHAR, SUM(t2.[Col2]))
FROM TBL t1 INNER JOIN TBL t2 on t1.col1 >= t2.col1
GROUP BY t1.col1
ORDER BY t1.col1 DESC

祝你好运！

Answer 3

如果您提供审核表的数据样本而不是结果集的数据，那么您可能会获得优化和准确的查询。

使用Sql 2012，

DECLARE @Audit TABLE (
    [col1]  datetime  NOT NULL
    ,[col2]  INT  NOT NULL
)

insert into @audit(col1,Col2)
VALUES
('03/05/2017',  1  )
,('03/04/2017',  20 )
,('03/03/2017',  10 )
,('03/02/2017',  5  )
,('03/01/2017',  10 )

;WITH CTE as
(
select col1 ,sum(col2) over(ORDER BY col1 desc  RANGE BETWEEN 
CURRENT ROW AND UNBOUNDED FOLLOWING) AS col2
from @Audit
)
SELECT * FROM cte   
order by col1 desc

Answer 4

您可以尝试以下内容。

IF OBJECT_ID('tempdb..#CumulativeSum') IS NOT NULL
    DROP TABLE #CumulativeSum

SELECT t1.col1, t1.col2 AS col2Actual, SUM(t2.col2) AS col2
INTO #CumulativeSum
FROM Audit t1
INNER JOIN Audit t2 on t1.col1 >= t2.col1
GROUP BY t1.col1, t1.col2
ORDER BY t1.col1

SELECT col1, col2 FROM #CumulativeSum ORDER BY col2 DESC

答案是从FiReTiTi建议的下方链接中复制的。

how to get cumulative sum

编辑 - 用于查询单个命令。

SELECT col1, col2 FROM(
    SELECT TOP 100 PERCENT t1.col1, t1.col2 AS col2Actual, SUM(t2.col2) AS col2
    FROM Audit t1
    INNER JOIN Audit t2 on t1.col1 >= t2.col1
    GROUP BY t1.col1, t1.col2
    ORDER BY t1.col1)x
ORDER BY col2 DESC

希望这有助于达到您的确切要求。

Answer 5

尝试以下查询

select [col1] = CONVERT(VARCHAR(10), DATEADD(HOUR, 8, a.date), 101) ,
       [Col2] = (select count(*) from Audit b where b.date<= DATEADD(HOUR, 8, a.date))
from Audit a
group by DATEADD(HOUR, 8, a.date)
order by CONVERT(VARCHAR(10), DATEADD(HOUR, 8, a.date), 101) desc

Answer 6

仅通过以下查询更改您的查询（此查询仅在您使用SQL SERVER 2012时有效）

试试这个：

std::shared_ptr<TaskLoop> t = std::make_shared<>(FunctorClass(o));

如何使用SQL创建数据累积报告？

6 个答案: