从Hibernate Query

Question

我的Hibernate存储库中有以下查询：

@Query("SELECT house FROM House house WHERE (6371 * acos(cos(radians((:oLat))) * cos(radians(house.lat)) * cos(radians(house.lng) - radians((:oLng))) + sin (radians((:oLat))) * sin(radians(house.lat)))) < (:dist)")
List<House> findByLatLng(@Param("oLat") Double oLat, @Param("oLng")Double oLng, @Param("dist")Double dist);

它返回了我距离原点一定距离内的房屋清单。现在，我该怎么办，还可以存储和返回（从原点到给定记录的距离）的值：

6371 * acos(cos(radians((:oLat))) * cos(radians(house.lat)) * cos(radians(house.lng) - radians((:oLng))) + sin (radians((:oLat))) * sin(radians(house.lat))))

有什么想法吗？

Answer 1

我不会写你的特定例子，但是这样的话：

SELECT something
  FROM (SELECT (personId * 78) AS something
          FROM people) alias
 WHERE something < 12345