您好我正在android studio上构建一个需要注册和登录的应用程序, 我的注册工作正常,而我的登录遇到麻烦,即使用户名和密码正确,我也会得到假布尔而不是真, 这是我的PHP文件:
`$con = mysqli_connect("localhost", "id1013905_trhtkv", "my password",` "id1013905_user");
$username = $_POST["username"];
$password = $_POST["password"];
$statement = mysqli_prepare($con, "SELECT * FROM user WHERE username = ?");
mysqli_stmt_bind_param($statement, "s", $username);
mysqli_stmt_execute($statement);
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement, $colUserID, $colName, $colUsername, $colAge, $colPassword);
$response = array();
$response["success"] = false;
while(mysqli_stmt_fetch($statement)){
if (password_verify($password, $colPassword)) {
$response["success"] = true;
$response["name"] = $colName;
$response["age"] = $colAge;
}
}
echo json_encode($response);
?>
我的登录活动:
package com.ben.owner.say_something;
import android.app.AlertDialog;
import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.toolbox.Volley;
import org.json.JSONException;
import org.json.JSONObject;
public class LoginActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login_activity);
final EditText etUsername = (EditText)findViewById(R.id.etUsername);
final EditText etPassword = (EditText)findViewById(R.id.etPassword);
final Button bLogin = (Button)findViewById(R.id.bLogin);
final TextView registerLink = (TextView)findViewById(R.id.tvRegisterHere);
registerLink.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent registerIntent = new Intent(LoginActivity.this, RegisterActivity.class);
LoginActivity.this.startActivity(registerIntent);
}
});
bLogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
final String username = etUsername.getText().toString();
final String password = etPassword.getText().toString();
final Response.Listener<String>responseListener = new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject jsonResponse = new JSONObject(response);
boolean success = jsonResponse.getBoolean("success");
if (success){
String name = jsonResponse.getString("name");
int age = jsonResponse.getInt("age");
Intent intent = new Intent(LoginActivity.this, UserAreaActivity.class);
intent.putExtra("name",name);
intent.putExtra("username",username);
intent.putExtra("age",age);
LoginActivity.this.startActivity(intent);
}else{
AlertDialog.Builder builder = new AlertDialog.Builder(LoginActivity.this);
builder.setMessage("Login Failed")
.setNegativeButton("Retry", null)
.create()
.show();
}
} catch (JSONException e) {
e.printStackTrace();
}
}
};
LoginRequest loginRequest = new LoginRequest(username,password,responseListener);
RequestQueue queue = Volley.newRequestQueue(LoginActivity.this);
queue.add(loginRequest);
}
});
}
}
我的登录请求:
package com.ben.owner.say_something;
import com.android.volley.Request;
import com.android.volley.Response;
import com.android.volley.toolbox.StringRequest;
import java.util.HashMap;
import java.util.Map;
/**
* Created by owner on 09/03/2017.
*/
public class LoginRequest extends StringRequest {
private static final String LOGIN_REQUEST_URL = "https://saysomething.000webhostapp.com/Login.php";
private Map<String, String> params;
public LoginRequest(String username,String password, Response.Listener<String> listener){
super(Request.Method.POST, LOGIN_REQUEST_URL, listener, null);
params = new HashMap<>();
params.put("username", username);
params.put("password", password);
}
@Override
public Map<String, String> getParams() {
return params;
}
}
答案 0 :(得分:0)
要找到您的错误,我建议您在回复中检索服务器值。
我的意思是
而不是
$response = array();
$response["success"] = false;
while(mysqli_stmt_fetch($statement)){
if (password_verify($password, $colPassword)) {
$response["success"] = true;
$response["name"] = $colName;
$response["age"] = $colAge;
}
}
echo json_encode($response);
使用
$response = array();
$response["success"] = false;
echo $statement;//or something like
while(mysqli_stmt_fetch($statement)){
if (password_verify($password, $colPassword)) {
echo $password;
echo $colPassword;
$response["success"] = true;
$response["name"] = $colName;
$response["age"] = $colAge;
}
}
echo json_encode($response);
或调试您的服务器端。看来你的服务器代码是错误的。
检查此示例