并行化Active Directory查询

时间:2017-03-09 10:22:09

标签: powershell active-directory

我想从所有域控制器的所有Active Directory用户获取所有lastlogon日期。这将生成包含所有用户及其最新登录日期的列表。我的脚本工作正常,但是可以将它更多地并行化吗?

目前只需一个用户查询所有20个域控制器大约需要1秒钟(Invoke-Parallel正在帮助很多)。

这里的问题是我们有~120k用户

以下是代码:

. 'D:\scripts\InPa\Invoke-Parallel-lite-nolog.ps1'

function Get-UsersLastLogon{
    $AllDCs = ([System.DirectoryServices.ActiveDirectory.Domain]::GetCurrentDomain().domainControllers).Name
    $AllUser = ((New-Object System.DirectoryServices.DirectorySearcher("(&(objectCategory=User))")).FindAll().Properties).samaccountname

    foreach($SamAccountName in $AllUser){
        $Latest = $AllDCs | Invoke-Parallel -Throttle 60 -ScriptBlock {
        $de=[adsi]"LDAP://$_"
        $UserSeacher = (New-Object System.DirectoryServices.DirectorySearcher($de,"(&(objectCategory=User)(samaccountname=$Using:SamAccountName))")).FindAll().Properties

        $co = New-Object System.Object
        $co | Add-Member -type NoteProperty -name SamAccountName -value $Using:SamAccountName
        $co | Add-Member -type NoteProperty -name lastlogon -value ([datetime]::FromFileTime([string]$UserSeacher.lastlogon))
        $co

        }
        $Latest | Sort-Object -Property lastlogon -Descending | Select-Object -First 1
    }
}

Get-UsersLastLogon | Export-Csv -Path D:\UsersLastLogon.csv -Delimiter ';' -NoTypeInformation

你有想法加快这个速度吗?

1 个答案:

答案 0 :(得分:6)

假设您有20个域控制器,那么您目前正在进行20 * 120000 + 2个LDAP查询 - 这几乎是250个查询。

您可以执行的操作是查询每个DC 一次,并按照每个DC一次性检索所有用户:

function Get-UsersLastLogon{

    # Gather all DC names
    $AllDCs = ([System.DirectoryServices.ActiveDirectory.Domain]::GetCurrentDomain().domainControllers).Name

    # In parallel, query the DCs for ALL users
    $AllEntries = $AllDCs | Invoke-Parallel -Throttle 60 -ScriptBlock {
        $de=[adsi]"LDAP://$_"
        $UserSeacher = New-Object System.DirectoryServices.DirectorySearcher($de,"(&(objectCategory=User))")
        [void]$UserSeacher.PropertiesToLoad.Add('lastLogon')
        $Users = $UserSeacher.FindAll().Properties

        foreach($User in $Users){
            New-Object psobject -Property @{
                SamAccountName = $User.SamAccountName
                LastLogon = ([datetime]::FromFileTime([string]$User.lastlogon))
            }
        }
    }

    # Group all the results by user name
    foreach($UserEntry in $AllEntries |Group-Object SamAccountName){
        # Emit the newest entry per username
        $UserEntry.Group |Sort-Object -Property LastLogon -Descending | Select-Object -First 1
    }
}