Android Espresso:测试未分配ID的动态创建按钮

时间:2017-03-09 09:04:15

标签: android android-espresso

我有多个按钮,这些按钮是在for循环中动态创建的,并且没有ID。我需要对这些按钮进行自动化测试。我怎么能用Espresso做到这一点?这是创建各种按钮的for循环:

 for (int i = 0; i < numberOfSamples; i++) {
            TableRow.LayoutParams vl = new TableRow.LayoutParams(30,30);
            Button b = new Button(context);
            b.setId(((blockNumber * 10000)+i));
            //b.setHint(i);
            //b.setHint(blockNumber);
    //      double selectedGrade = 0;
    //      if(FinalSurvey.multi[blockNumber][i] != 0){
    //          selectedGrade = FinalSurvey.multi[blockNumber][i];
    //      }
    //      final int makeHighlight = selectedGrade;
            b.setBackgroundDrawable(context.getResources().getDrawable(R.drawable.a));
            b.setAlpha(1.0f);
            b.setOnClickListener(new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    ViewsAdding va = new ViewsAdding();
                    va.showGrades(context, v, grades);
                    view = v;
                    maincontext = context;
                }
            });

            if(i%5 == 0){
                innerLayout = new LinearLayout(context);
                innerLayout.setOrientation(LinearLayout.HORIZONTAL);
                innerLayout.setLayoutParams(innerparams);
                vl.setMargins(5, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                if(i == numberOfSamples-1){
                    mainLinearLayout.addView(innerLayout);
                }
                b = null;
            }else if (i%5 ==1) {
                vl.setMargins(22, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                if(i == numberOfSamples-1){
                    mainLinearLayout.addView(innerLayout);
                }
                b = null;
            }else if (i%5 ==2) {
                vl.setMargins(25, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                mainLinearLayout.addView(innerLayout);
                b = null;
            }else if (i%5 ==3) {
                innerLayout = new LinearLayout(context);
                innerLayout.setOrientation(LinearLayout.HORIZONTAL);
                innerLayout.setLayoutParams(innerparams);
                vl.setMargins(35, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                if(i == numberOfSamples-1){
                    mainLinearLayout.addView(innerLayout);
                }
                b = null;
            }else{
                vl.setMargins(30, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                mainLinearLayout.addView(innerLayout);
                b = null;
            }
        }
        return mainLinearLayout;
    }

1 个答案:

答案 0 :(得分:4)

在您创建按钮的代码中,根据具体情况为按钮添加标签:

button.setTag("someTag");

所以在你的情况下,你可以在你的if子句中做到:

       if(i%5 == 0){
            ...
            b.setTag("case0-" + i);
            ...
        }else if (i%5 ==1) {
            ...
            b.setTag("case1-" + i);
            ...
        }
        ...

然后在您的测试中,您可以使用此按钮获取或单击它:

onView(allOf(withTagValue(is((Object) "case0-0")), isDisplayed())).perform(click());
onView(allOf(withTagValue(is((Object) "case0-0")), isDisplayed())).perform(click());

您也可以用循环替换“case0-0”字符串以重新生成标记