Question

在数据库中，我有专栏。 - 我的查询是 -

SELECT Emp_Name, Schedule 
FROM emp_schedule

重新生成此结果集：

Emp_Name        Schedule

M.S.Cave        10:00 AM - 7:00 PM Semi Flexi
M.S.Cave        10:00 AM - 7:00 PM Semi Flexi
K.V.Boreta      9:00 AM - 6:00 PM Fixed
K.V.Boreta      9:00 AM - 6:00 PM Fixed
R.M.Mendoza     Branch 8:30 AM to 5:30 PM Sunday RD
R.M.Mendoza     Branch 8:30 AM to 5:30 PM Sunday RD

但是我想只显示“时间表”列，只考虑时间，忽略文本。

Emp_Name        Schedule

M.S.Cave        10:00 AM - 7:00 PM
M.S.Cave        10:00 AM - 7:00 PM
K.V.Boreta      9:00 AM - 6:00 PM
K.V.Boreta      9:00 AM - 6:00 PM
R.M.Mendoza     8:30 AM to 5:30 PM
R.M.Mendoza     8:30 AM to 5:30 PM

没有TRIM，添加列或编辑我的表等可以做到这一点吗？

Answer 1

试试这个

我使用REVERSE，PATINDEX，SUBSTRING来实现它。忽略CTE，因为我只想使用临时表。

;WITH CTE (Emp_Name, Schedule)
AS (
    SELECT 'M.S.Cave', '10:00 AM - 7:00 PM Semi Flexi'
    UNION ALL
    SELECT 'M.S.Cave', '10:00 AM - 7:00 PM Semi Flexi'
    UNION ALL
    SELECT 'K.V.Boreta', '9:00 AM - 6:00 PM Fixed'
    UNION ALL
    SELECT 'K.V.Boreta', '9:00 AM - 6:00 PM Fixed'
    UNION ALL
    SELECT 'R.M.Mendoza', 'Branch 8:30 AM to 5:30 PM Sunday RD'
    UNION ALL
    SELECT 'R.M.Mendoza', 'Branch 8:30 AM to 5:30 PM Sunday RD'
    )
, CTE2 AS (
    SELECT *
    , SUBSTRING(Schedule, PATINDEX('%[0-9]%', Schedule), LEN(Schedule)) SS
    FROM CTE
    )
SELECT *
,REVERSE(SUBSTRING(REVERSE(SS), PATINDEX('%[0-9]%', REVERSE(SS)) - 3, LEN(SS)))
FROM CTE2

结果就像

+-------------+-------------------------------------+-------------------------------+--------------------+
|  Emp_Name   |              Schedule               |              SS               |  (No column name)  |
+-------------+-------------------------------------+-------------------------------+--------------------+
| M.S.Cave    | 10:00 AM - 7:00 PM Semi Flexi       | 10:00 AM - 7:00 PM Semi Flexi | 10:00 AM - 7:00 PM |
| M.S.Cave    | 10:00 AM - 7:00 PM Semi Flexi       | 10:00 AM - 7:00 PM Semi Flexi | 10:00 AM - 7:00 PM |
| K.V.Boreta  | 9:00 AM - 6:00 PM Fixed             | 9:00 AM - 6:00 PM Fixed       | 9:00 AM - 6:00 PM  |
| K.V.Boreta  | 9:00 AM - 6:00 PM Fixed             | 9:00 AM - 6:00 PM Fixed       | 9:00 AM - 6:00 PM  |
| R.M.Mendoza | Branch 8:30 AM to 5:30 PM Sunday RD | 8:30 AM to 5:30 PM Sunday RD  | 8:30 AM to 5:30 PM |
| R.M.Mendoza | Branch 8:30 AM to 5:30 PM Sunday RD | 8:30 AM to 5:30 PM Sunday RD  | 8:30 AM to 5:30 PM |
+-------------+-------------------------------------+-------------------------------+--------------------+

Answer 2

我尝试如下：

select Emp_name,
        reverse(SUBSTRING(reverse(Schedule),charindex(' MP ',REVERSE(Schedule)),len(Schedule)))
        ,substring(Schedule,charindex(' AM ',Schedule)-5,charindex(' PM ',Schedule)-charindex(' AM ',Schedule)+8)
        from emp_schedule

在列上获取时间而忽略文本

2 个答案: