Question

def main():
    x = [randint(1,100) for i in range(1,100)]
    return x

这将返回100个随机数bt 1和100.每次调用该函数时，它都会返回不同的数字序列。我想要的是每次都得到相同的数字序列。也许将结果保存到某事上？

Answer 1

你可以提供一些固定的种子。

apply plugin: 'com.android.application'

android {
    compileSdkVersion 25
    buildToolsVersion "25.0.1"
    defaultConfig {
        applicationId "abtech.waiteriano.com.waitrer"
        minSdkVersion 18
        targetSdkVersion 25
        versionCode 1
        versionName "1.0"
        testInstrumentationRunner "android.support.test.runner.AndroidJUnitRunner"
    }
    buildTypes {
        release {
            minifyEnabled false
            proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
        }
    }
}

dependencies {
    compile fileTree(dir: 'libs', include: ['*.jar'])
    androidTestCompile('com.android.support.test.espresso:espresso-core:2.2.2', {
        exclude group: 'com.android.support', module: 'support-annotations'
    })
    compile project(':jtds-1.3.1')
    compile 'com.android.support:support-v4:25.2.0'
    compile 'com.android.support:appcompat-v7:25.2.0'
    compile 'com.android.support:design:25.2.0'
    compile 'com.roughike:bottom-bar:1.3.9'
    compile 'com.android.support:recyclerview-v7:25.2.0'
    compile 'com.android.support.constraint:constraint-layout:1.0.0-alpha8'
    testCompile 'junit:junit:4.12'
}

有关种子的更多信息：random.seed(): What does it do?

Answer 2

以下是代码

后的基本示例

import random
s = random.getstate()

print([random.randint(1,100) for i in range(10)])

random.setstate(s)
print([random.randint(1,100) for i in range(10)])

在两次调用中，您获得相同的输出。关键是，您可以随时检索并稍后重新分配rng的当前状态。

Answer 3

In [19]: for i in range(10):
    ...:     random.seed(10)
    ...:     print [random.randint(1, 100) for j in range(5)]
    ...:
    ...:
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]
[58, 43, 58, 21, 82]

必须在对随机的新调用之前调用random.seed函数。

In [20]: random.seed(10)

In [21]: for i in range(10):
    ...:     print [random.randint(1,10) for j in range(10)]
    ...:
[5, 6, 3, 9, 9, 7, 2, 6, 4, 3]
[10, 10, 1, 9, 7, 4, 3, 7, 5, 7]
[7, 2, 8, 10, 10, 7, 1, 1, 2, 10]
[4, 4, 9, 4, 6, 5, 1, 6, 9, 2]
[3, 5, 1, 5, 9, 7, 6, 9, 2, 6]
[4, 7, 2, 8, 1, 2, 9, 10, 5, 5]
[3, 3, 7, 2, 2, 5, 2, 7, 9, 8]
[5, 4, 5, 1, 8, 4, 4, 1, 5, 6]
[4, 9, 7, 3, 6, 10, 6, 7, 1, 5]
[5, 5, 5, 6, 6, 5, 2, 5, 10, 5]

Python - 生成相同的随机数

3 个答案: