Question

我有json响应如下

[{"name":"kannur hub","TotalAmount":1840,"child":[{"sub":"Sale Of Products @ 12 % Tax","amount":345,"sub":"sos","amount":1020,"sub":"Boss","amount":475}]},{"name":"Calicut Hub","TotalAmount":7000,"child":[{sub":"cop","amount":3500,"sub":"SALES ACCOUNT","amount":3500}]}]

我想要一个像这样的json而不是上面的格式

[{"sub":"Boss","Name":"kannur hub","Amount":475.00},{"sub":"sos","Name":"kannur hub","Amount":1020.00},{"sub":"cop","Name":"Calicut Hub","Amount":3500.00},{"sub":"SALES ACCOUNT","Name":"Calicut Hub","Amount":3500.00},{"sub":"Sale Of Products @ 12 % Tax","Name":"kannur hub","Amount":345.00}]

因此，每当我从hibernate投影中检索子组时，结果将删除sum值并返回单个值

ProjectionList proj = Projections.projectionList();
        proj.add(Projections.groupProperty("offId.officeProfileName").as("Name"));
        proj.add(Projections.groupProperty("accId.accHeadName").as("sub"));
        proj.add(Projections.sum("accountsDataValue").as("Amount"));
        crit.setProjection(proj);

hibernate查询是，

db.collection.find().sort({team:1}).exec(fn)

我使用Spring启动应用程序和带有java 1.8版本的postgresql数据库

Answer 1

如果你想获得你想要的json结果，你应该创建一个自定义DTO，请参阅下面的例子。

class Child {
    String sub;
    Long amount;
}

class Dto {
   String name;
   Long totalAmount;
   List<Child> child;
}

然后组成你的Dto并添加必要的孩子。下面是示例，假设您已经拥有db：

的结果

如果您的回报是List<Child>，那么您可以这样做..

Dto dto = new Dto();
dto.addAll(rs);
dto.setName("name");
dto.setTotalAmount(totalAmount);
return dto;

如果rs结果不是List<Child>，你可以这样做......

Dto dto = new Dto();
//assumed rs contains the db child results.
for(int i=0; i<rs.length; i++) {
    Child child = new Child(rs.get("sub"), rs.get("amount"))
    dto.getChild().add(child)
}
dto.setName("name");
dto.setTotalAmount(totalAmount);
return dto;

有效的结果JSON如下所示：

{
        "name":"kannur hub",
        "TotalAmount":1840,
        "child":[
            {
                "sub":"Sale Of Products @ 12 % Tax",
                "amount":345,
            },
            {
                "sub":"sos",
                "amount":1020,
            },
            {
                "sub":"Boss",
                "amount":475
            }
        ]
    },
    {
        "name":"Calicut Hub",
        "TotalAmount":7000,
        "child":[
            {
                "sub":"cop",
                "amount":3500
            },
            {
                "sub":"SALES ACCOUNT",
                "amount":3500
            }
        ]
    }

想从hibernate json响应中嵌套json格式

1 个答案: