比方说,我们有一个列表列表,我想找出x位置的内容:
((a,b,c),(d,e,f),(g,h,i),(i,x,l))
我如何找出存在的内容并将其保存到变量中?
答案 0 :(得分:1)
mystuff = (('a','b','c'),('d','e','f'),('g','h','i'),('i','x','l'))
lookfor = 'f' # example
for i, a in enumerate(mystuff):
if lookfor in a:
print('found {} in tuple {} at index {}'.format(lookfor, i, a.index(lookfor)))
输出:
found f in tuple 1 at index 2
答案 1 :(得分:0)
这是一个如何在列表列表中找到索引项目的示例
list_of_lists=[['a','b','c'],['d','e','f'],['g','h','i'],['i','x','l']]
#create variable consisting of sublist 2
find_sublist_two = (list_of_lists)[1]
print (find_sublist_two)
#create variable consisting of 2nd item of sublist 2
find_2nd_item_in_sublist_two = (list_of_lists)[1][1]
print (find_2nd_item_in_sublist_two)