我创建了一个数据库。在那个数据库中,我创建了一个表。然后我写下面的代码来从创建的表中检索数据。我检索了表中存在的所有元素。现在我想为检索到的列的所有行添加复选框。任何人都可以帮助我,并在下面的代码中建议更改。
<?php
// Check connection
if ($link === false) {
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Attempt select query execution
$sql = "SELECT * FROM fruits";
if ($result = mysqli_query($link, $sql)) {
if (mysqli_num_rows($result) > 0) {
echo "<table>";
echo "<tr>";
echo "<th>PID</th>";
echo "<th>Fruit Name</th>";
echo "<th>Quantity(Kgs)</th>";
echo "<th>Price</th>";
echo "</tr>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['PID'] . "</td>";
echo "<td>" . $row['Fruit Name'] . "</td>";
echo "<td>" . $row['Quantity(Kgs)'] . "</td>";
echo "<td>" . $row['Price'] . "</td>";
echo "<td>" . $row["submitted"] . "<td><input type ='checkbox' value = '" . $row['PID '] . "'PID = '" . $row['PID '] . "'> </td></td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else {
echo "No records matching your query were found.";
}
} else {
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);
?>
答案 0 :(得分:0)
检查此代码我认为它会起作用
<?php
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Attempt select query execution
$sql = "SELECT * FROM fruits";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){ ?>
<table>
<tr>
<th>PID</th>
<th>Fruit Name</th>
<th>Quantity(Kgs)</th>
<th>Price</th>
<th> </th>
</tr>
<?php
while($row = mysqli_fetch_array($result)){ ?>
<tr>
<td><?=$row['PID']?></td>
<td><?=$row['Fruit Name']?></td>
<td><?=$row['Quantity(Kgs)'] ?></td>
<td><?=$row['Price']?></td>
<td><?=$row["submitted"]?><input type ='checkbox'
value="<?=$row['PID']?>" PID="<?=$row['PID']?>"></td>
</tr>
<?php } ?>
</table>
<?php // Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);
?>
答案 1 :(得分:0)
我在代码中修改了while循环。试试这个。
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['PID'] . "</td>";
echo "<td>" . $row['Fruit Name'] . "</td>";
echo "<td>" . $row['Quantity(Kgs)'] . "</td>";
echo "<td>" . $row['Price'] . "</td>";
echo "<td>" .$row["submitted"]. "<input type ='checkbox' value=" .$row["PID"]. "></td>";
echo "</tr>";
}