我们有一个Azure ARM模板,它正在为Microsoft.Web / site添加appsetting。
"resources": [
{
"apiVersion": "2016-03-01",
"name": "myazurefunction",
"type": "Microsoft.Web/sites",
"properties": {
"name": "myazurefunction",
"siteConfig": {
"appSettings": [
{
"name": "MY_SERVICE_URL",
"value": "[concat('https://myservice-', parameters('env'), '.domain.ca')]"
}
]
}
}
}
]
我们还有四个parameters.environment.json
个文件。例如,这是parameters.dev.json
的内容。
{
"$schema": "https://schema.management.azure.com/schemas/2015-01-01...",
"contentVersion": "1.0.0.0",
"parameters": {
"env": {
"value": "dev"
}
}
}
模板及其参数有利于约定优于配置。这在大多数情况下运行良好,并导致以下MY_SERVICE_URL
值。
问题是我们想要打破dev
环境的约定。也就是说,我们希望它有MY_SERVICE_URL
看起来像这样:
我们如何配置ARM模板以打破仅一个环境的约定?
我的第一个是使用这样的条件,但是这样的ARM函数似乎不可用。
"name": "MY_SERVICE_URL",
"value": "[parameters('env') -eq 'dev'
? 'https://abc123.foo.bar.baz.ca'
: concat('https://myservice-', parameters('env'), '.domain.ca')]"
答案 0 :(得分:2)
只需创建一个取决于参数的变量:
"parameters": {
...
"DeploymentType": {
"type": "string",
"allowedValues": [
"Dev",
"Prod"
]
}
...
"variables": {
"Dev": "https://some_service-ci.domain.com",
"Prod": "https://abc123.foo.bar.baz.com",
"DeploymentVariable": "[variables(parameters('DeploymentType'))]",
...
"appSettings": [
"name": "MY_SERVICE_URL",
"value": "[variables('DeploymentVariable')]"
]
...
好的,这是怎么回事。传入参数'DeploymentType',它可以是PROD或DEV。如果您传递DEV "DeploymentVariable": "[variables(parameters('DeploymentType'))]",
- 此评估结果为"[variables('Dev')]"
并获得"Dev": "https://some_service-ci.domain.com",
答案 1 :(得分:0)
对于问题中的示例,答案最终看起来像这样:
"variables": {
"myServiceUrl_default": "[concat('https://myservice-', parameters('env'), '.domain.ca')]",
"myServiceUrl_dev": "https://abc123.foo.bar.baz.ca",
"myServiceUrl_ci": "[variables('myServiceUrl_default')]",
"myServiceUrl_qa": "[variables('myServiceUrl_default')]",
"myServiceUrl_prod": "[variables('myServiceUrl_default')]",
"myServiceUrl": "[variables(concat('myServiceUrl_', 'parameters('env')'))]"
},
...
"appSettings: [
{
"name": "MY_SERVICE_URL",
"value": "[variables('myServiceUrl')]"
}
]