我试图将数据发送到php文件以保存在数据库中,但我没有任何回复。如果选中复选框,则[obj] [idCheckbox] = 1,否则[obj] [idCheckbox] = 0。
发送
的文件 var i=0;
var objetoTodasPermissoes = function(){};
var objTodasPermissoes = new objetoTodasPermissoes();
$.each($(".classePermissoes"), function(){
objTodasPermissoes[$(this)[0].id] = 0
i++;
});
$.each($(".classePermissoes:checked"), function(){
alert('ok');
objTodasPermissoes[$(this)[0].id] = 1;
});
console.log(objTodasPermissoes);
$.each($("#userList tr"),function(){
alert(this.id);
var iduser = this.id;
$.ajax({
url:'../json/usuarioperm/savePermissions.php',
data:({
idusuario:iduser,
objTodasPermissoes:objTodasPermissoes,
}),
success:function(a){
Alert("Saved!");
}
});
});
}
savePermissions.php文件。
$iduser = $_POST["iduser"];
$perm_usuarios = $_POST["objTodasPermissoes"]["perm_usuarios"];
$perm_importar = $_POST["objTodasPermissoes"]["perm_importar"];
$perm_log = $_POST["objTodasPermissoes"]["perm_log"];
$perm_proto = $_POST["objTodasPermissoes"]["perm_proto"];
$perm_limpeza = $_POST["objTodasPermissoes"]["perm_limpeza"];
$perm_lixeira = $_POST["objTodasPermissoes"]["perm_lixeira"];
$perm_relatusuarios = $_POST["objTodasPermissoes"]["perm_relatusuarios"];
$perm_deptos = $_POST["objTodasPermissoes"]["perm_deptos"];
$perm_deptospastas = $_POST["objTodasPermissoes"]["perm_deptospastas"];
$perm_empresas = $_POST["objTodasPermissoes"]["perm_empresas"];
mysql_query("UPDATE hospital.users set
perm_usuarios=".$perm_usuarios.",
perm_importar=".$perm_importar.",
perm_log=".$perm_log.",
perm_proto=".$perm_proto.",
perm_limpeza=".$perm_limpeza.",
perm_lixeira=".$perm_lixeira.",
perm_relatusuarios=".$perm_relatusuarios.",
perm_deptos=".$perm_deptos.",
perm_deptospastas=".$perm_deptospastas.",
perm_empresas=".$perm_empresas." where id=".$iduser) or die (mysql_error());
谢谢。
答案 0 :(得分:2)
PHP非常有趣,因为当涉及Ajax时,它不像其他形式那样从$_POST
拉出来。实际上你需要阅读php://input
这是一个很小的例子
$data = file_get_contents("php://input");
$response = json_decode($data, true ); // True converts to array; blank converts to object
$emailAddr = $response["email"];
希望你能成功申请。
编辑:您可以添加filter_var命令来删除不良字符并清理输入。
$emailAddr = filter_var($response["email"], FILTER_SANITIZE_EMAIL);
$firstName = filter_var($response["firstName"], FILTER_SANITIZE_STRING);
在调试时,我强烈建议您使用Chrome的开发者模式,使用'网络'标签。在底部附近找到你的ajax电话,你可以查看确切的标题信息。