Question

我刚刚计划制作一个程序，我需要使用DBHost，DBUser，DBPassword和DBName连接USER的数据库，以便在MySQL服务器上保存未来所需的值。为此，我写了这样的代码：

＆＃13;

<?php session_start(); ?>
<?php

require('functions.php');
iq_add_style( 'DBConForm_Styles' , 'assets/scripts/css/iq_styles' , 'stylesheet' , 'css' );

function IQ_DB_Form(){
  ?>

  <form id="iq-dbconform" method="post" action="<?php $_SERVER['PHP_SELF'] ?>">
    <label>Server Host:&nbsp;<input type="text" maxlength="15" placeholder="localhost" name="host-name" /></label>
    <label>Database User:&nbsp;<input type="text" maxlength="15" placeholder="root" name="user-name" /></label>
    <label>Password:&nbsp;<input type="password" maxlength="15" placeholder="User Password" name="user-pass" /></label>
    <label>Name of the Database:&nbsp;<input type="text" maxlength="20" placeholder="developing_house" name="db-name" /></label>
    <input type="submit" value="Connect" name="dbconbtn" />&nbsp;<input type="reset" value="Reset" name="dbresetbtn" />
  </form>

  <?php
}
IQ_DB_Form();

// Database connection
$dbhost = $_POST['host-name'];
$dbuser = $_POST['user-name'];
$dbpass = $_POST['user-pass'];
$dbname = $_POST['db-name'];

$db_details = array(
    'host' => $dbhost,
    'user' => $dbuser,
    'password' => $dbpass,
    'dbname' => $dbname,
);
$IQcon = mysqli_connect($db_details['host'],$db_details['user'],$db_details['password'],$db_details['dbname']);



// Check connection
if (mysqli_connect_errno())
  {
  echo "Looks like an Error connecting IQubex Database: " . mysqli_connect_error();
  }

// Store Values in Session
foreach ($_POST as $key => $value) {
    ${$key} = $value;
    $_SESSION[$key] = $value;
}

echo $_SESSION['db-name'];
echo $_SESSION['user-pass'];
echo $_SESSION['user-name'];

// Perform queries
if ($IQcon){
mysqli_query($IQcon,"CREATE TABLE `Persons` (
  `FirstName` varchar(30) NOT NULL,
  `LastName` varchar(60) NOT NULL,
  `Age` int(255) NOT NULL,
);");
mysqli_query($IQcon,"CREATE TABLE `MadBoys` (
  `FirstName` varchar(30) NOT NULL,
  `LastName` varchar(60) NOT NULL,
  `Age` int(255) NOT NULL,
);");
mysqli_close($IQcon);
}
else{
  echo "There seems a problem with your server.";
}
?>

＆＃13;

我已在会话中保存了数据库配置表单值，因此当我写echo $_SESSION['db-name']时，将打印插入的数据库名称。但是当页面重新加载，再回到页面上，或类似的东西时，所有的值都会重置！因此，我不希望我的用户一次又一次地连接数据库。我希望它能够永远保存，以便我可以为下一个程序步骤工作。

Answer 1

您可以检查会话中是否保存了值。如果它们不连接到db，则获取值并将它们保存在DB中：

请参阅以下示例：

session_start();
if(isset($_SESSION['stored-in-db']))
{
    //USE SESSION VALUES
}
else
{
$dbhost = $_POST['host-name'];
$dbuser = $_POST['user-name'];
$dbpass = $_POST['user-pass'];
$dbname = $_POST['db-name'];

$db_details = array(
    'host' => $dbhost,
    'user' => $dbuser,
    'password' => $dbpass,
    'dbname' => $dbname,
);
  $IQcon = mysqli_connect($db_details['host'],$db_details['user'],$db_details['password'],$db_details['dbname']);
  foreach ($_POST as $key => $value)
  {
      $_SESSION[$key] = $value;
  }
  $_SESSION['stored-in-db] = true;
 }

Answer 2

尝试添加

session_start();

在您使用会话的页面顶部。

如何将$ _POST变量设置为永久保存在$ _SESSION中？

2 个答案: