将分区计算结果存储在数组中

Question

我的脚本中有以下简单的除法计算：

<?php

$total = 1001;
$people = 5;

$division= $total / $people;

echo "division = ".$division;

?>

这会输出division = 200.2。

是否可以将其存储起来，如下所示？

$division[0] = 200;
$division[1] = 200;
$division[2] = 200;
$division[3] = 200;
$division[4] = 201;

Answer 1

// initital conditions
$total = 1001;
$people = 5;

// count what is the minimal value, that all the results will have
$value = floor($total / $people);
$result = array_fill(0, $people, $value);

// distribute missing "+1"s as needed in the result
$overheads = $total - $value * $people;
for ($i = 0; $i < $overheads; $i++)
    $result[$i]++;

// voila...
var_dump($result);

Answer 2

试试这个：

$total = 1001;
$people = 5;
$division = array();
$extra = $total % $people; // Stores the extra number i.e 1
$i = 1;
while ($i <= $people) {
    /* For the last array element, add the extra number */
    if ($i == $people) {  
        $division[] = floor($total/$people) + $extra;
    } else {
        $division[] = floor($total/$people);
    }   
    $i++;
}

Answer 3

试试这个，

$total = 1001;
$people = 5;
$division = [];
$difference = intval($total%100);
for($i =0 ; $i < $people; $i++){
    $division[] = ($i == $people - 1) ? (intval($total/ $people) + $difference) : intval($total/ $people);
}
print_r($division);
die;

Answer 4

<?php

$total = 1001;
$people = 5;

$division = array();

$division[] = round($total / $people);

echo "division = ".$division[0];
?>

此数组对象将为您提供从数组中存储和检索的值。