无法向html输入表单显示php的值

时间:2017-03-08 09:38:38

标签: javascript php jquery html arrays

我想在html上显示数组值。数组值来自php。

选择选项正在运行,但未显示下一个字符串值。

像这张照片......

enter image description here

(它没有工作"获得价值" ..我想......)

源代码在这里......

PHP -

<?php
   $arr[0]="11.1.35.132";
?>

php代码只有...数组值。该值将发布到HTML。

HTML -

    <html>
<head>
<link rel="stylesheet" type="text/css" href="../css/main.css">
<script type="text/javascript">

function getR() {
    document.forms['save']['cnt_mme'].value = "<?php echo count($arr); ?>";
    document.forms['save']['mmeremoteip'].value = <?php echo json_encode($arr[0]); ?>;
}
</script>
</head>
<body onLoad="getR();">
<form name="save" method="post">
<h1>TEST</h1>
<table>

<tr><td>No. of IP</td>
<td id="cnt_mme">
<script>
  var mmeip = "<?php echo count($arr); ?>";
  var opt = document.getElementById("cnt_mme");
  var html="<select size=\"1\"";

  for(i = 0; i < mmeip; i++) {
      html += "<option value=\"" + i + "\">" + i +"</option>";
  }
  html + "</select></td>";
  opt.innerHTML = html;
</script>
  <tr>
   <td class="param">Remote IP</td>
   <td><input type="text" class="inputParam" size="20" maxlength="15" name="mmeremoteip" id="MME REMOTE IP"></td>
  </tr>
</tr>

</table>
</body>
</html>

和view-source是....

   <head>
<link rel="stylesheet" type="text/css" href="../css/main.css">
<script type="text/javascript">

function getR() {
    document.forms['save']['cnt_mme'].value = "3";
    document.forms['save']['mmeremoteip'].value = "10.1.35.31";
}
</script>
</head>
<body onLoad="getR();">
<form name="save" method="post">
<h1>TEST</h1>
<table>

<tr><td>No. of MME Remote IP</td>
<td id="cnt_mme">
<script>
  var mmeip = "3";
  var opt = document.getElementById("cnt_mme");
  var html="<select size=\"1\"";

  for(i = 0; i < mmeip; i++) {
      html += "<option value=\"" + i + "\">" + i +"</option>";
  }
  html + "</select></td>";
  opt.innerHTML = html;
</script>
  <tr>
   <td class="param">MME Remote IP</td>
   <td><input type="text" class="inputParam" size="20" maxlength="15" name="mmeremoteip" id="MME REMOTE IP"></td>
  </tr>
</tr>

</table>
</body>
</html>

我认为getR()函数有问题。我不确切地知道。

2 个答案:

答案 0 :(得分:0)

 document.forms['save']['mmeremoteip'].value = <?php echo $arr[0]; ?>;

不要编码,没有必要。

答案 1 :(得分:0)

此处select标签未关闭,并尝试在您正在脚本中访问的数组中添加更多值。

例如add

<?php
$arr=array();

   $arr[0]="11.1.35.132";
    $arr[1]="11.1.35.133";
     $arr[2]="11.1.35.135";

?>

添加更改关闭html中的select标记:

<script>
  var mmeip = "<?php echo count($arr); ?>";
  var opt = document.getElementById("cnt_mme");
  alert(mmeip)
  var html="<select size=\"1\">";

  for(var i = 0; i < mmeip; i++) {
      html += "<option value="+ i + ">" + i +"</option>";
  }
  html + "</select></td>";
  opt.innerHTML = html;
</script>

您将获得带有0,1,2选项值的选项列表。