Question

以下查询返回以下输出。

输出

BrandName   Amount
brand1      314.00
brand1      24.00
brand2      75.00
brand2      48.00

所需的输出是获得每个品牌的总金额，如下所示

BrandName   Amount
brand1      338.00
brand2      123.00

查询

SELECT Brands.BrandName,
  SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge - ((SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge) * Orders.Discount / 100) AS Amount

FROM dbo.Orders

INNER JOIN dbo.Outlets
  ON dbo.Orders.OutletID = dbo.Outlets.OutletID


INNER JOIN dbo.OrderDetails
  ON dbo.OrderDetails.OrderID = dbo.Orders.OrderID
INNER JOIN dbo.Brands
  ON dbo.Brands.BrandID = dbo.Outlets.BrandID

GROUP BY 
Orders.OrderID,
dbo.Orders.DeliveryCharge,
Orders.Discount,
Brands.BrandName

Answer 1

您可以使用Common Table Expression作为您的场景

With MyGroupCte as 
(
SELECT Brands.BrandName,
  SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge - ((SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge) * Orders.Discount / 100) AS Amount

FROM dbo.Orders

INNER JOIN dbo.Outlets
  ON dbo.Orders.OutletID = dbo.Outlets.OutletID


INNER JOIN dbo.OrderDetails
  ON dbo.OrderDetails.OrderID = dbo.Orders.OrderID
INNER JOIN dbo.Brands
  ON dbo.Brands.BrandID = dbo.Outlets.BrandID

GROUP BY 
Orders.OrderID,
dbo.Orders.DeliveryCharge,
Orders.Discount,
Brands.BrandName
)
SELECT BrandName, SUM(Amount) FROM MyGroupCte 
GROUP BY BrandName;

Answer 2

这样做：

SELECT grp.BrandName,sum(Amount)as Total_Amount from
(SELECT Brands.BrandName,
  SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge - ((SUM((OrderDetails.Quantity * OrderDetails.UnitPrice)) + Orders.DeliveryCharge) * Orders.Discount / 100) AS Amount

FROM dbo.Orders

INNER JOIN dbo.Outlets
  ON dbo.Orders.OutletID = dbo.Outlets.OutletID


INNER JOIN dbo.OrderDetails
  ON dbo.OrderDetails.OrderID = dbo.Orders.OrderID
INNER JOIN dbo.Brands
  ON dbo.Brands.BrandID = dbo.Outlets.BrandID

GROUP BY 
Orders.OrderID,
dbo.Orders.DeliveryCharge,
Orders.Discount,
Brands.BrandName) as grp
group by BrandName

使用子查询获得总和

2 个答案: