比较并从python中的列表中提取字符串

Question

LIST=['insert_job: aaa', 'box_name: bbb', 'insert_job: ccc', 
      'box_name: ddd', 'insert_job: eee', 'insert_job: fff', 
      'box_name: ggg'] 

在上面的列表中，如果有2个连续insert_job: ('insert_job: eee', 'insert_job: fff')，那么我想首先打印insert_job:，在这种情况下将insert_job: eee。

Answer 1

您可以使用itertools.groupby

实现此目的

from itertools import groupby

LIST = ['insert_job: aaa', 'box_name: bbb', 'insert_job: ccc',
        'box_name: ddd', 'insert_job: eee', 'insert_job: fff',
        'box_name: ggg']

for k, g in groupby(LIST, lambda s: s.split(':')[0]):
    if k == 'insert_job':
        items = list(g)
        if len(items) > 1:
            print(*items[:-1])

Answer 2

因为你需要物品的顺序，所以你不需要字典。尝试以下内容

seen = 0
for i in LIST:
    if i.startswith("insert_job"):
        if seen:
            continue
        else: 
            seen = 1
            print i
    else: 
         seen=0
         # print i