Question

我想模仿jest客户端，所以我可以测试

@Override
public List<Person> findAll() {
    SearchResult result = null;
    SearchSourceBuilder searchSourceBuilder = new SearchSourceBuilder();
    searchSourceBuilder.query(QueryBuilders.matchAllQuery());
    Search search = new Search.Builder(searchSourceBuilder.toString()).addIndex(personIndexName)
            .addType(personTypeName).build();
    try {
        result = client.execute(search);
        if (!result.isSucceeded()) {
            return null;
        }

    } catch (IOException e) {
        logger.error("The search can't be completed " + e.getMessage());
    }
    List<SearchResult.Hit<Person, Void>> hits = result.getHits(Person.class);
    return hits.stream().map(this::getPerson).collect(Collectors.toList());
}

我想模拟jest，所以它抛出IOException并做一些其他的测试，我尝试过像这样的模拟：

        when(mockJestClient.execute(search)).thenThrow(IOException.class);
    when(mockJestClient.execute(null)).thenThrow(IOException.class);

    elasticsearchPersonRepository = new ElasticsearchPersonRepository(mockJestClient);

当我打电话给考试时，

无济于事

  @Test(expected = IOException.class)
public void findAll() throws Exception {

    elasticsearchPersonRepository.findAll();

}

它抛出空指针异常而不是IOExcept。我究竟做错了什么？我该如何模拟JestClient？

Answer 1

你不应该使用＆＃39;搜索＆＃39;也不是＆＃39; null＆＃39;但特别的＆＃39;任何＆＃39;执行的参数。如果它是Mockito（其他模拟框架具有类似的功能）

when(mockJestClient.execute(ArgumentMatchers.any(Search.class))).thenThrow(IOException.class);

如何模拟JestClient，elasticSearch

1 个答案: