Question

我无法找到为什么它不允许我在函数中使用getline但它让我使用cin。这是代码：

#include <iostream>
#include <fstream>

void Read(),Write();
std::string line;

int main()
{
    std::string choise;
    std::cout << "Would you like to write or read the Journal?" << 

std::endl;
        std::cin >> choise;
        switch (choise[0]){
            case ('w'):{
                Write();
                break;
            }
            case ('r'):{
                Read();
                break;
            }
            default :{
                std::cout << "Something went wrong" << std::endl;
            }
        }


        return 0;
    }

void Read()
{
    std::ifstream myfile("/home/turry/Documents/CPP/Journal/test.txt"); // Hardcoded address
    std::cout << "\x1B[2J\x1B[H"; //clear the screen
    while ( getline (myfile,line))
    {
        std::cout << line << std::endl;
    }

}

void Write()
{
    std::string lines;
    std::cout << "\x1B[2J\x1B[H"; //clear the screen
    std::cout << "Write your thoughts or/and what you did today :D" << std::endl;
    std::ofstream myfile("/home/turry/Documents/CPP/Journal/test.txt",std::ios::app); // Hardcoded address
    while (true) {
        getline(std::cin, lines);
        if (lines.empty()){
            break;
        }
        std::cout << "DEBUG\n";

    }
    std::cout << lines << std::endl;

}

Answer 1

以下代码应修复

 using std::getline;

请见Live Demo。

或者写

while (std::getline (myfile,line))
    // ^^^^^

还要考虑明确包含string标头。从documentation所需要的。

至少使用

std::string line;

要求你

#include <string>

Answer 2

std::getline是字符串标题的一部分。

#include <string> should fix the issue.

无法在函数C ++中获取输入

2 个答案: