Question

我有一个员工对象，我想将一些值复制到一个新对象中。我正在使用Typescript来复制它们，但我收到了错误。

打字稿代码：

employee = [
    { "empId": "59C", "empDesc": "Software","location":"Dallas"},
    { "empId": "AMI", "empDesc": "Hardware", "location":"San Francisco"}
  ];
  companies : any;
  for (let c of this.employee) {
      this.companies.push({
        empDesc: c.empDesc,
        empId: c.empId
      })
    };
  console.log("Companies",this.companies);

Plunker代码链接：

https://plnkr.co/edit/CnBR4JouNhzH3DWm7QCo?p=preview

Answer 1

您需要在函数中运行该代码。在这里，我在构造函数中运行它。您只能在类中声明变量。

您还需要使用空数组初始化companies。

  employee = [
    { "empId": "59C", "empDesc": "Software","location":"Dallas"},
    { "empId": "AMI", "empDesc": "Hardware", "location":"San Francisco"}
  ];
  companies : any = [];


  constructor(){
    for (let c of this.employee) {
      this.companies.push({
        empDesc: c.empDesc,
        empId: c.empId
      })
    };
   console.log("Companies",this.companies);

  }

Answer 2

有几个问题，

你必须编写代码以及某些功能

constructor(){
    for (let c of this.employee) {
      this.companies.push({
        empDesc: c.empDesc,
        empId: c.empId
      })
    };
  console.log("Companies",this.companies);
 }

并初始化公司财产，

查看更新后的Plunker!!

希望这会有所帮助!!

Answer 3

这对我有用：

public employee: any[] = [];
public companies: any[] = [];

ngOnInit() {
    this.employee = [
    { "empId": "59C", "empDesc": "Software","location":"Dallas"},
    { "empId": "AMI", "empDesc": "Hardware", "location":"San Francisco"}
    ];


    for (let c of this.employee) {
      let temp = [{
        empDesc: c.empDesc,
        empId: c.empId
      }]
      this.companies.push(temp);
    };
    console.log("Companies",this.companies);
}

Angular 2 - 无法使用typescript将值从一个对象复制到另一个对象

3 个答案: