我有一个小函数,它接受一个字符串并返回其MD5哈希值。问题是,它需要一个UTF8字符串,我需要它来计算用iso-8859-1(~ansi)编码的字节数组的哈希值。
如何更改以下代码以接受字节数组,然后返回其散列值?
static func md5(_ string: String) -> String {
let context = UnsafeMutablePointer<CC_MD5_CTX>.allocate(capacity: 1)
var digest = Array<UInt8>(repeating:0, count:Int(CC_MD5_DIGEST_LENGTH))
CC_MD5_Init(context)
CC_MD5_Update(context, string, CC_LONG(string.lengthOfBytes(using: String.Encoding.utf8)))
CC_MD5_Final(&digest, context)
context.deallocate(capacity: 1)
var hexString = ""
for byte in digest {
hexString += String(format:"%02x", byte)
}
return hexString
}
棘手的部分是CC_MD5_Update调用。感谢。
答案 0 :(得分:1)
您可以轻松修改函数以获取任意字节
数组作为参数。 CC_MD5_Update
映射到Swift为
func CC_MD5_Update(_ c: UnsafeMutablePointer<CC_MD5_CTX>!, _ data: UnsafeRawPointer!, _ len: CC_LONG) -> Int32
您可以将数组作为UnsafeRawPointer
参数传递:
func md5(bytes: [UInt8]) -> String {
var context = CC_MD5_CTX()
var digest = Array<UInt8>(repeating:0, count:Int(CC_MD5_DIGEST_LENGTH))
CC_MD5_Init(&context)
CC_MD5_Update(&context, bytes, CC_LONG(bytes.count))
CC_MD5_Final(&digest, &context)
return digest.map { String(format: "%02hhx", $0) }.joined()
}
(我也简化了一点。)
或者,传递一个Data
参数:
func md5(data: Data) -> String {
var context = CC_MD5_CTX()
var digest = Array<UInt8>(repeating:0, count:Int(CC_MD5_DIGEST_LENGTH))
CC_MD5_Init(&context)
data.withUnsafeBytes {
_ = CC_MD5_Update(&context, $0, CC_LONG(data.count))
}
CC_MD5_Final(&digest, &context)
return digest.map { String(format: "%02hhx", $0) }.joined()
}
然后可以用作
let s = "foo"
if let data = s.data(using: .isoLatin1) {
let hash = md5(data: data)
print(hash)
}
Swift 5: 更新
import CommonCrypto
func md5(data: Data) -> String {
var context = CC_MD5_CTX()
var digest = Array<UInt8>(repeating:0, count:Int(CC_MD5_DIGEST_LENGTH))
CC_MD5_Init(&context)
data.withUnsafeBytes {
_ = CC_MD5_Update(&context, $0.baseAddress, CC_LONG(data.count))
}
CC_MD5_Final(&digest, &context)
return digest.map { String(format: "%02hhx", $0) }.joined()
}
答案 1 :(得分:0)
如果您确定自己的字符串&#39;仅包含utf8字符,使用string.utf8调用CC_MD5_Update:
CC_MD5_Update(context, string.utf8, CC_LONG(string.lengthOfBytes(using: String.Encoding.utf8)))
swift中的字符串很有趣&#39;,这是关于这个主题的好读物:https://oleb.net/blog/2016/08/swift-3-strings/
答案 2 :(得分:0)
// requires a bridging header with this:
// #import <CommonCrypto/CommonCrypto.h>
func MD5(_ string: String) -> String? {
let length = Int(CC_MD5_DIGEST_LENGTH)
var digest = [UInt8](repeating: 0, count: length)
if let d = string.data(using: String.Encoding.utf8) {
d.withUnsafeBytes { (body: UnsafePointer<UInt8>) in
CC_MD5(body, CC_LONG(d.count), &digest)
}
}
return (0..<length).reduce("") {
$0 + String(format: "%02x", digest[$1])
}
}