Gson - 如何存储属性和值

Question

如何分别将“id”和“name”的值存储为var newflags = '<%= newflag %>'; console.log(newflags); if (newflags === "null" ) { document.getElementById('newflag').style.visibility = "hidden"; } else if(newflags === "true" ){ document.getElementById('newflag').style.visibility = "visable"; } ？

目前，转出HashMap<Integer, String>会给我pseudoStations。迭代将为每个列表元素提供[{"id":0,"name":"London"}, {"id":1,"name":"Nottingham"}]。

主要类

JsonObject

电台经理班级

public static void main(String[] args) {
    Gson gson = new Gson();
    BufferedReader br = null;

    try {
        br = new BufferedReader(new FileReader("stations.json"));
        StationManager sm = gson.fromJson(br, StationManager.class);
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } finally {
        if (br != null) {
            closeBufferedReader(br);
        }
    }
}

stations.json

public class StationManager {
    @SerializedName("pseudoStations")
    @Expose
    private List<JsonObject> pseudoStations = null;

    public void setPseudoStations(List<JsonObject> pseudoStations) {
        this.pseudoStations = pseudoStations;
    }
}

Answer 1

您可以从StationManager循环遍历JSONObject列表并将数据添加到HashMap。

public static void main(String[] args) {
    Map<Integer, String> output = new HashMap<Integer, String>();
    Gson gson = new Gson();
    BufferedReader br = null;

    try {
        br = new BufferedReader(new FileReader("stations.json"));
        StationManager sm = gson.fromJson(br, StationManager.class);
        List<JsonObject> listOfObjs = sm.getPseudoStations();
        for(JsonObject obj: listOfObjs){
            output.put(obj.getInt("id"), obj.getString("name"));
        }
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } finally {
        if (br != null) {
            closeBufferedReader(br);
        }
    }
}