Question

我使用以下命令在目录结构中递归查找字符串。

find . -exec grep -l samplestring {} \;

但是当我在一个大型目录结构中运行命令时，会有一长串的

grep: ./xxxx/xxxxx_yy/eee: Is a directory
grep: ./xxxx/xxxxx_yy/eee/local: Is a directory
grep: ./xxxx/xxxxx_yy/eee/lib: Is a directory

我想省略上面的结果。只需显示带有字符串的文件名即可。有人可以帮忙吗？

Answer 1

每当你说find .时，该实用程序将返回当前目录结构中的所有元素：文件，目录，链接......

如果你只想找到文件，就这么说吧！

find . -type f -exec grep -l samplestring {} \;
#      ^^^^^^^

但是，您可能希望查找包含字符串的所有文件：

grep -lR "samplestring"

Answer 2

grep -s或grep --no-messages

如果你希望在多个地方使用这个代码，那么值得阅读the GNU grep documentation中的可移植性说明：

-s --no-messages Suppress error messages about nonexistent or unreadable files. Portability note: unlike GNU grep, 7th Edition Unix grep did not conform to POSIX, because it lacked -q and its -s option behaved like GNU grep’s -q option.1 USG-style grep also lacked -q but its -s option behaved like GNU grep’s. Portable shell scripts should avoid both -q and -s and should redirect standard and error output to /dev/null instead. (-s is specified by POSIX.)

Omit＆＃34;是一个目录＆＃34;在Unix中使用find命令时的结果

2 个答案: