Question

我有一个包含一些条目的数组。我用“dummydata”替换了真实数据。但是“dummydata”与array [0]和array [1]的值相同。正如您所看到的那样，某些键存在一些差异：

如何使上面的数组合并所有相同的数据，但覆盖不同的数据。例如，我想要完成的结果：

Array
(
    [0] => Array
        (
            [contact_id] => dummydata
            [customer_code] => dummydata
            [customer_name] => dummydata
            [territory] => dummydata       
            [firstname] => dummydata
            [lastname] => dummydata
            [contact_type_description] => dummydata
            [contact_is_primary] => 1
            [mailing_street] => dummydata
            [mailing_postal_code] => dummydata
            [mailing_city] => dummydata
            [mailing_country] => dummydata
            [email] => dummydata
            [mobile_phone] => dummydata
            [phone] => dummydata
            [is_processed] => 0
            [exact_email_found] => 0
            [half_email_found] => 0
            [possible_by_postal_code] => 1 // * This becomes one from the merging
            [found_first_name] => 0
            [found_last_name] => 1 // * This becomes one from the merging
        )


    [1] => Array
        (
            [contact_id] => dummydata-different
            [customer_code] => dummydata-different
            [customer_name] => dummydata-different
            [territory] => dummydata-different  
            [firstname] => dummydata-different
            [lastname] => dummydata-different
            [contact_type_description] => dummydata-different
            [contact_is_primary] => 0
            [mailing_street] => dummydata-different
            [mailing_postal_code] => dummydata-different
            [mailing_city] => dummydata-different
            [mailing_country] => dummydata-different
            [email] => 
            [mobile_phone] => 
            [phone] => 
            [is_processed] => 0
            [exact_email_found] => 0
            [half_email_found] => 0
            [possible_by_postal_code] => 0
            [found_first_name] => 1
            [found_last_name] => 0
        )

用PHP提供的功能尝试了不同的东西，但这让我很困惑。

Answer 1

你可以这样做：

$result = array_map("unserialize", array_unique(array_map("serialize", $input_array)));

$input_array是具有重复值的数组。

所以这里基本上发生的是第一个数组被转换为单维数组，然后删除重复值，然后再将它转换为多维数组。

Answer 2

我说保持简单（和快速）：

foreach ($arr[0] as $k=>$v) {
    if ($v > $arr[1][$k]) $arr[1][$k] = $v;
}

array_shift($arr);

注意：如果您要比较的两个项目不在数组的开头，请使用unset和array_values代替array_shift。

如何组合 - 覆盖数组中的键值对

2 个答案: