从php调用mysql存储过程时出错

Question

我已经从php触发了存储过程。我也传递了输入参数，如图所示。

$id = 1;
$nameDetail = 'raj';
$result = mysqli_query('CALL InsertDetails($id,$nameDetail)');

但低于错误。

mysqli_query() expects at least 2 parameters, 1 given ...

请提出解决方案。

Answer 1

问题是你没有设置mysqli连接。请试试这个

$connection = mysqli_connect('localhost','username','password','db');
    $result = mysqli_query($connection,'CALL InsertDetails($id,$nameDetail)');

Answer 2

您需要传递连接作为第一个参数：

// connect to DB
$connect = mysqli_connect("127.0.0.1", "my_user", "my_password", "my_db");

// run procedure
$result = mysqli_query($connect, 'CALL InsertDetails($id,$nameDetail)');