Question

 <p class="">
    Teacher:
<a href="/name/nm12345/?ref_=adv_0"
>Scott</a>
             <span class="ghost">|</span> 
    Students:
<a href="/name/nm12345/?ref_=adv_1"
>Benedict</a>, 
<a href="/name/nm12345/?ref_=adv_2"
>Chiwetel</a>, 
<a href="/name/nm12345/?ref_=adv_3"
>Rachel</a>, 
<a href="/name/nm12345/?ref_=adv_4"
>Benedict Wong</a>
    </p>

我想提取老师的名字 - ＆＃34; Scott＆＃34;这是＆＃34;老师＆＃34;的标签。并提取所有学生＆＃39;名称标记为＆＃34;学生＆＃34;。我试过了： soup.find(lambda tag:tag)并返回

<a href="/name/nm12345/?ref_=adv_0"
>Scott</a>

我认为这不是一种正确的方法。代码应该如何实际提取＆＃34;老师＆＃34;和＃34;学生＆＃34;标签？

Answer 1

假设您的HTML块在解析其他页面时不会有太大变化，您可以按类找到p标记（您的示例没有）并验证Teacher文本是否存在。

如果是从p标签获取.contents[1]，这是元素上的第一个a。

接下来查找a属性与您的教师不匹配的所有href代码。

示例：

from bs4 import BeautifulSoup

example = """<p class="">
Teacher:
<a href="/name/nm12345/?ref_=adv_0"
>Scott</a>
         <span class="ghost">|</span> 
Students:
<a href="/name/nm12345/?ref_=adv_1"
>Benedict</a>, 
<a href="/name/nm12345/?ref_=adv_2"
>Chiwetel</a>, 
<a href="/name/nm12345/?ref_=adv_3"
>Rachel</a>, 
<a href="/name/nm12345/?ref_=adv_4"
>Benedict Wong</a>
</p>"""

soup = BeautifulSoup(example, "html.parser")

Classroom = soup.find(lambda x: "Teacher" in x.get_text())

if Classroom is not None:

    Teacher = Classroom.contents[1]
    TeacherUrl = Teacher["href"]

    Students = Classroom.find_all(lambda tag: tag.has_attr('href') and TeacherUrl not in tag["href"])

    print (Teacher.text)
    for Student in Students:
        print (Student.text)

哪个输出：

斯科特

笃

切瓦特

拉结

Benedict Wong

用美丽的汤提取几个价值观

1 个答案: