Question

我有一张表，其中包含经理和日期的操作。行动可以是"0" or "1"。我希望按日期分组并计算按日期和经理分组的"0" and "1"次操作。这是我的代码。

SELECT COUNT( * ) ,
  manager_id,
  action,
  CAST( `created_at` AS DATE ) AS DATE
FROM `prerequesttours_history`
GROUP BY CAST( `created_at` AS DATE ),
  anager_id,
  action

我想这样结果：

| count where action = 1 | count where action = 0 | manager_id | date

Result of query

Answer 1

尝试将其选为子查询。

SELECT SUM([Count]), manager_id, action, [Date]
FROM
(
    SELECT COUNT( * ) 'Count' , manager_id, action, CAST(  `created_at` AS DATE ) 'Date'
) main
GROUP BY manager_id, action, [Date]

Answer 2

如果action仅使用这两个值，则可以执行以下操作：

SELECT manager_id, date(`created_at`) AS DATE,
       SUM(action) as count_1, SUM(1 - action) as cnt_0
FROM  `prerequesttours_history`
GROUP BY manager_id, date(created_at);

如果您想更明确地比较：

SELECT manager_id, date(`created_at`) AS DATE,
       SUM(action = 1) as count_1, SUM(action = 1) as cnt_0
FROM  `prerequesttours_history`
GROUP BY manager_id, date(created_at);

注意：使用cast()转换为日期很好。但是，MySQL为此目的提供了更简单的函数date()。

SUB查询按日期和经理分组

2 个答案: