pg-promise与发电机的交易让我感到奇怪 这就是我想要的:
这是我的代码:
db.tx(function (t) {
return t.task.call(params, getOrRegisterUser).then(function (user) {
params.masterId = user.id; // NOTICE : MY USER ID DATABASE
return t.batch([
t.task.call(params, registerNewPhones),
t.task.call(params, registerNewPlate),
t.task.call(params, registerNewSubscriptions),
t.task.call(params, getOrRegisterCurrentParkingIfProvided)
]).then(function (result) {
params.ParkingId = (result[3] !== undefined) ? result[3].id : null;
return t.task.call(params, registerCall);
})
});
}).then(function () {
// job done
resolve();
}).catch(function (err) {
console.log(err);
reject(err);
});
我在第二个生成器(registerNewPhones)上收到此错误消息:
severity: 'ERREUR',
code: '23503',
detail: 'La clé (customer)=(3) n\'est pas présente dans la table « users ».',
有什么方法可以解决这个问题?我试过这样的交易:https://github.com/vitaly-t/pg-promise#nested-transactions或https://github.com/vitaly-t/pg-promise#synchronous-transactions但是在某些未知的情况下我仍然在某个地方出错。
由于
PS:我知道这些发电机的实施并非如此......
编辑:如果你真的想看代码
let squel = require('squel');
// squel with PostgresSQL syntax
let squelPostgres = squel.useFlavour('postgres');
registerNewPhones:
// Register all new phones numbers for user
function * registerNewPhones(t) {
let params = t.ctx.context;
let findPhonesForUserQuery = squelPostgres
.select()
.from("HELPDESK.phones")
.field("number")
.where("customer = ?", params.masterId)
.toString();
let registerPhoneForUser = squelPostgres
.insert()
.into("HELPDESK.phones")
.set("customer", params.masterId);
// find the already known phone number(s) for this user
return t.any(findPhonesForUserQuery).then(function (result) {
// data
let phones = (params.hasOwnProperty("phones") ? params.phones : []);
let alreadyRegisteredPhones = result.map(function (element) {
return element.number;
});
// filter data
let phonesToRegister = phones.filter(function (aPhoneNumber) {
return alreadyRegisteredPhones.indexOf(aPhoneNumber) == -1;
});
// create queries
let queries = phonesToRegister.map(function (phone) {
return db.none(
registerPhoneForUser
.clone()
.set("number", phone)
.toString()
);
});
return t.batch(queries);
});
}
和生成器getOrRegisterUser:
function * getOrRegisterUser(t) {
let params = t.ctx.context;
// QUERIES:
let findUserQuery = squelPostgres
.select()
.from("HELPDESK.users")
.field("id")
.where("registered_id = ?", params.userId)
.toString();
let insertUserQuery = squelPostgres
.insert()
.into("HELPDESK.users")
.setFields({
name: params.userName,
registered_id: params.userId,
typeOfAccount: 'BASIC',
email: params.email
})
.returning('id')
.toString();
let user = yield t.oneOrNone(findUserQuery);
return yield user || t.one(insertUserQuery);
}
答案 0 :(得分:1)
问题出在ES6-Generator功能registerNewPhones
:
return t.any(findPhonesForUserQuery)...
它不会yield
承诺结果,这是ES6 Generator功能所必需的。
即。它一定是:
return yield t.any(findPhonesForUserQuery)...