可排序组件仅显示初始数组元素。将新值推入数组时,sortable不会显示它。
组件: 从' @ angular / core';
导入{Component}@Component({
selector: 'custom-item-template-demo',
templateUrl: './custom-item-template.html'
})
export class CustomItemTemplateDemoComponent {
public itemStringsLeft: any[] = [
'Windstorm',
'Bombasto',
'Magneta',
'Tornado'
];
public addItem() {
this.itemStringsLeft.push("new item");
}
}
模板:
<button type="button" (click)="addItem()">Add</button>
<template #itemTemplate let-item="item" let-index="index"><span>{{index}}: {{item.value}}</span></template>
{{itemStringsLeft.length}}
<pre>{{ itemStringsLeft | json }}</pre>
<bs-sortable
[(ngModel)]="itemStringsLeft"
[itemTemplate]="itemTemplate"
itemClass="sortable-item"
itemActiveClass="sortable-item-active"
placeholderItem="Drag here"
placeholderClass="placeholderStyle"
wrapperClass="sortable-wrapper"
></bs-sortable>
答案 0 :(得分:2)
解决方法:手动调用SortableComponent的writeValue
import { Component, ViewChild } from '@angular/core';
@Component({
selector: 'custom-item-template-demo',
templateUrl: './custom-item-template.html'
})
export class CustomItemTemplateDemoComponent {
public itemStringsLeft: any[] = [
'Windstorm',
'Bombasto',
'Magneta',
'Tornado'
];
@ViewChild(SortableComponent) sortableComponent: SortableComponent;
public addItem() {
this.itemStringsLeft.push("new item");
this.sortableComponent.writeValue(this.itemStringsLeft);
}
}
答案 1 :(得分:1)
重新分配列表值的另一种解决方法:
public addItem() {
this.itemStringsLeft.push("new item");
this.itemStringsLeft = this.itemStringsLeft.slice();
}
答案 2 :(得分:0)
应添加import { SortableComponent } from 'ngx-bootstrap';
它将正常工作。
答案 3 :(得分:0)
传播操作员在此问题上对我来说效果很好:
addItem(){
this.itemStringsLeft = [...this.itemStringsLeft, {name: 'Windstorm', range: 5}];
}