Question

我有一个如下所示的数组

var someData = [“123”，“456”];

我正在尝试从上面的

创建以下JSON

[{
    "link_video": "123",  
     "video_id":456 
}, {
    "link_video": "456"
   "video_id": "123"
}]

我试过以下

var myvideos = [];
var someData = ["123", "456"];
for (var i = 0; i < someData.length; i++) {
  myvideos.push({
    "link_video": someData[i],
    "video_id": someData[i],
  });
}
console.log(JSON.stringify(myvideos));

但正在形成的输出是

[{"link_video":"123","video_id":"123"},{"link_video":"456","video_id":"456"}]

http://jsfiddle.net/cod7ceho/465/

你能否告诉我如何正确地形成这个JSON

Answer 1

好吧，你需要为每次迭代访问数组中的两个元素，所以你应该更新你的循环，然后通过访问索引i的元素及其在数组中的直接兄弟来追加对象两次： / p>

＆＃13;

var myvideos = [];
var someData = ["123", "456"];

for (var i = 0; i < someData.length; i+=2)
{
    myvideos.push({
       "link_video": someData[i],
       "video_id": someData[i+1],
    },
    {
       "link_video": someData[i+1],
       "video_id": someData[i],
    });
}
console.log(myvideos);

＆＃13;

Answer 2

试试他的，这可能就是你要找的东西

还有更多数据，例如@font-face { font-family: 'SunriseInternational'; src: url('fonts/SunriseInternational.otf') format('otf'), url('fonts/SunriseInternational.ttf') format('truetype'); unicode-range: U+20-21, U+3F, U+41-5A, U+61-7A; } h1, h2, .h1, .h2 { font-family: 'SunriseInternational', 'Branding-Medium', sans-serif; font-size: 8vw; color: #ffffff; letter-spacing:2px; }

["123", "456", "789"]

var myvideos = [];
var someData = ["123", "456"];
for (var i = 0; i < someData.length; i++) {
  myvideos.push({
    "link_video": someData[i],
    "video_id": someData[(i == 0 ? (i + 1) : i == (someData.length - 1) ? (0) : (i + 1))],
  });
}
console.log(JSON.stringify(myvideos));

Answer 3

只需手动喜欢这个lol

＆＃13;

var myvideos = [];
var someData = ["123", "456"];

console.log(JSON.stringify([{"link_video": someData[0], "video_id": someData[1]}, {"link_video": someData[1], "video_id": someData[0]}]));

＆＃13;

如何动态创建以下JSON

3 个答案: