c #json拉请求

Question

我的JSON如下：

 string url = "https://kgsearch.googleapis.com/v1/entities:search?languages=tr&query=Necati+Şaşmaz&limit=1&key=AIzaSyB_w5S8Bv3P4zn7pqu6if49_4bHx9YMmSY";
 HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
 string jsonVerisi = "";
 using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
 {
      StreamReader reader = new StreamReader(response.GetResponseStream());
      //jsonVerisi adlı değişkene elde ettiği veriyi atıyoruz.
      jsonVerisi = reader.ReadToEnd();
 }

如何使用json获取所选图像的位置？

Answer 1

有两种方法可以实现这个目标

1. 如果返回的JSON内容架构（结构）始终相同，请尝试创建一个类，如下所示

注意：这些类是使用json2csharp

生成的

    public class Context {
    [JsonProperty("@vocab")] //This is to map the property name with @symbol in JSON content to this class property
     public string vocab { get; set; }
     public string goog { get; set; }
     public string EntitySearchResult { get; set; }
     public string detailedDescription { get; set; }
     public string resultScore { get; set; }
     public string kg { get; set; }
    }

    public class DetailedDescription {
     public string articleBody { get; set; }
     public string url { get; set; }
     public string license { get; set; }
    }

    public class Result {
     [JsonProperty("@id")]
     public string id { get; set; }
     public string name { get; set; }
     [JsonProperty("@type")]
     public List<string> type { get; set; }
     public string description { get; set; }
     public DetailedDescription detailedDescription { get; set; }
    }

    public class ItemListElement {
     [JsonProperty("@type")]
     public string type { get; set; }
     public Result result { get; set; }
     public double resultScore { get; set; }
    }

    public class SearchResult {
     [JsonProperty("@context")]
     public Context context { get; set; }
     [JsonProperty("@type")]
     public string type { get; set; }
     public List<ItemListElement> itemListElement { get; set; }
    }

然后尝试使用JsonConvert from Newtonsoft Json.NET反序列化jsonVerisi值，如下所示

    using(HttpWebResponse response = request.GetResponse() as HttpWebResponse) {
            using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
                //jsonVerisi adlı değişkene elde ettiği veriyi atıyoruz.
                jsonVerisi = reader.ReadToEnd();

                //Deserialize
                var searchResult = JsonConvert.DeserializeObject<SearchResult>(jsonVerisi);
                //Now you could get the needed value as below
                if(searchResult != null) {
                    foreach(var item in searchResult.itemListElement) {
                        var resultTypes = item.result != null ? item.result.type : null;

                        //Iterate through resultTypes to get the list of values
                        //e.g. for person
                        //var personType = resultTypes[1];
                    }
                }
            }
        }

1. 使用类型Newtonsoft Json.NET JObject（提供类似于Dictionary<string, object>和JSON key or property name的元素访问）而不是创建新类，并反序列化JSON内容，如下所示。 / p>

   using(HttpWebResponse response = request.GetResponse() as HttpWebResponse)     {
           using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
               //jsonVerisi adlı değişkene elde ettiği veriyi atıyoruz.
               jsonVerisi = reader.ReadToEnd();
   
               var searchResult = JsonConvert.DeserializeObject<JObject>(jsonVerisi);
               if(searchResult != null) {
                   var itemListElement = searchResult["itemListElement"];
                   if(itemListElement != null) {
                       foreach(var item in itemListElement.ToList()) {
                           var result = item["result"];
                           var resultTypes = result != null && result["@type"].HasValues ? result["@type"].Values<string>().ToList() : null;
   
                           //Iterate through resultTypes to get the list of values
                           //e.g. for person
                           //var personType = resultTypes[1];
                       }
                   }
               }
           }
       }
   

我希望这会对你的情况有所帮助！

提示：最好使用HttpClient类型，它有许多有用的方法来执行HTTP请求。