我来到这里另一个问题我已经工作了大约5个小时但没有运气。 我有一个像下面的图像表。
我已成功将数据插入其中。
现在我想通过使用下面的视图,控制器和Model类来更新插入的数据。 我的观看课程
<form role="form" method="post" enctype="multipart/form-data" action="<?php echo base_url('admin/updateCategory'); ?>">
<div class="box-body">
<div class="form-group">
<input type="hidden" value='<?php echo $catDataForEdit->cat_id; ?>' name="id_hidden">
<label for="exampleInputEmail1">Category Name</label>
<input type="text" class="form-control" id="exampleInputEmail1" name="category_name" placeholder="Category Name" value='<?php echo $catDataForEdit->category_name; ?>' >
</div>
<div class="form-group">
<label for="exampleInputEmail1">Upload Category Icon</label>
<!--input type="text" class="form-control" id="exampleInputEmail1" placeholder="Category Icon"-->
<p class="grey-color mt-0">Icon Size: Width: 26px, Height: 28px and Icon Format: .png</p>
<input type="file" name="cat_icon" value='<?php echo $catDataForEdit->iconName; ?>'>
</div>
<div class="form-group">
<label for="exampleInputEmail1">Upload Category Image</label>
<p class="grey-color mt-0">Image Size: Width: 175px, Height: 120px and Image Format: .png</p>
<input type="file" name="cat_image" value='<?php echo $catDataForEdit->imageName; ?>'>
</div>
</div>
<!-- /.box-body -->
<div class="box-footer box-footer-border">
<div class="row">
<div class="col-lg-6 col-md-6 col-sm-12 col-xs-12">
<input type="submit" class="btn btn-primary" name="update_cat_submit" value="Modify">
</div>
</div>
我的Controller Admin.php:
public function updateCategory(){
$data = array();
$targetDir = "images/dynamic/";
$prevcatIconName; $prevCatImageName;
$catIconName; $category_name; $catImageName;
$targetFilePathIcon; $targetFilePathImage;
$date; $unix_time;$hidden_id;
$hidden_id = $this->input->post('id_hidden');
if ($this->input->post('update_cat_submit')) {
$this->form_validation->set_rules('category_name', 'Category Name', 'trim|required');
if ($this->form_validation->run() == false) {
$this->modifyCategory($hidden_id);
}else{
$category_name = $this->input->post('category_name');
//Category Icon
if ( !empty($_FILES["cat_icon"]["name"])) {
//getting values from view
$catIconName = basename($_FILES["cat_icon"]["name"]);
$targetFilePathIcon = $targetDir . $catIconName;
$iconFileType = pathinfo($targetFilePathIcon,PATHINFO_EXTENSION);
//allow certain file formats
$allowTypes = array('jpg','png','jpeg','gif');
if(in_array($iconFileType, $allowTypes)){
//upload file to server
if(move_uploaded_file($_FILES["cat_icon"]["tmp_name"], $targetFilePathIcon)){
// echo "The file ".$fileName. " has been uploaded.";
//Category Image
if ( !empty($_FILES["cat_image"]["name"])) {
$catImageName = basename($_FILES["cat_image"]["name"]);
$targetFilePathImage = $targetDir . $catImageName;
$imageFileType = pathinfo($targetFilePathImage,PATHINFO_EXTENSION);
// echo $catIconName . ','. $catImageName;
//allow certain file formats
$allowTypes = array('jpg','png','jpeg','gif');
if(in_array($imageFileType, $allowTypes)){
//upload file to server
if(move_uploaded_file($_FILES["cat_image"]["tmp_name"], $targetFilePathImage)){
// echo "The file ".$fileName. " has been uploaded.";
$date = date('Y-m-d H:i:s');
$unix_time=human_to_unix($date);
//insert Category Icon into db and get CatIconId
$fields = array(
'image_name' => $catIconName,
'modified_at' => $unix_time,
'status' => 'a'
);
//print_r($fields);
$iconId = $this->img_model->updateImages($fields);
//echo $iconId;
//insert Category Image
$fields = array(
'image_name' => $catImageName,
'modified_at' => $unix_time,
'status' => 'a'
);
$imageId = $this->img_model->updateImages($fields);
//echo $iconId . ',' .$imageId;
echo $imageId;
//echo $unix_time;
if ($imageId != "" && $iconId != "" ) {
$next_fields = array(
'cat_name' => $category_name,
'cat_icon' => $iconId,
'cat_image' =>$imageId,
'modified_at'=>$unix_time,
'status' =>'a'
);
// print_r($next_fields); die();
$result = $this->cat_model->updateCatNames($hidden_id,$next_fields);
if ($result) {
//$this->Category();
redirect(base_url('admin/Category'));
//$this->load->view('admin/category');
}else{
$data['error_msg'] = 'there is problem with your input';
}
}
}else{
$data['error_msg'] = 'Sorry, there was an error uploading your image.';
$this->modifyCategory($hidden_id);
}//move_uploaded_file if else loop close
}else{
$data['error_msg'] = 'Sorry, only JPG, JPEG, PNG, GIF images are allowed to upload.';
$this->modifyCategory($hidden_id);
}//in_array if else loop close
}else{
$data['error_msg'] = 'Please select a image to upload.';
$this->modifyCategory($hidden_id);
}//empty file verification close
}else{
$data['error_msg'] = 'Sorry, there was an error uploading your Icon.';
$this->modifyCategory($hidden_id);
}//move_uploaded_file if else loop close
}else{
$data['error_msg'] = 'Sorry, only JPG, JPEG, PNG, GIF icons are allowed to upload.';
$this->modifyCategory($hidden_id);
}//in_array if else loop close
}else{
$data['error_msg'] = 'Please select a icon to upload.';
$this->load->view('admin/modify-category', $data);
}
}
}
}
我的模型类Img_model:
public function updateImages($fields){
$id = $this->input->post('id_hidden');
$this->db->where('id', $id);
$query = $this->db->update('images', $fields);
if($this->db->affected_rows() > 0){
$this->db->where($fields);
$result = $this->db->get('images')->row()->id;
//echo $result;
return $result;
//I have tried like below to get the last insert id but unable to get.
//return $this->db->insert_id();
}else{
return false;
}
}//close update Images
我的模型Cat_model:
public function updateCatNames($hidden_id,$next_fields){
$this->db->where('id', $hidden_id);
$this->db->update('categories', $next_fields);
if($this->db->affected_rows() > 0){
return true;
}else{
return false;
}
}
我试图从我的Img_model类中获取最新的插入记录ID,但无法获取它。有人可以帮帮忙吗? 提前谢谢!
答案 0 :(得分:0)
试试这个:
if( $this->db->update('categories', $next_fields) )
{
echo $hidden_id;
}
$this->db->update()
在TRUE / FALSE
执行查询时返回successful / failed
。所以上面的代码只有在查询成功执行时才会echo $hidden_id
。
答案 1 :(得分:0)
首先Try this
其次,您的表格图片中没有cat_id字段。如何在图像和类别表之间创建关系。请参阅下面的示例图片
我有一个property_images表,我有这样的property_id我也可以拥有该属性的多个图像。但是,由于只有一个类别图像,因此在图像表中放置category_id会使查询结构更加简单。
您只需更新包含您要发送的类别ID的记录,并返回完整记录,以防您想从中获取记录的ID。
您的案例
$fields = array(
'image_name' => $catImageName,
'modified_at' => $unix_time,
'status' => 'a'
);
$imageId = $this->img_model->updateImages($fields);
您正在使用上面的代码来更新您从视图中发送类别ID的图像表
<input type="hidden" value='<?php echo $catDataForEdit->cat_id; ?>' name="id_hidden">
并且在您的图片模型中,您将获得该类别ID以更新图片记录
$id = $this->input->post('id_hidden');
$this->db->where('id', $id);
$query = $this->db->update('images', $fields);
现在你想获得你更新的图像ID,你可以通过这段代码得到它
$st=$this->db->select('*')->from('images')->WHERE('image_name',$fields['image_name'])->get()->result_array();
$updatedRecordId=$st[0]['id']
// Now you can return it or use it.
但这对我没有任何意义。
答案 2 :(得分:0)
在您的模型类Img_model上:
public function updateImages($fields){
$id = $this->input->post('id_hidden');
$this->db->where('id', $id);
$query = $this->db->update('images', $fields);
if($this->db->affected_rows() > 0){
return $id;
// $id is your updated record id because it is unique.
}else{
return false;
}
}