Question

到目前为止，这是for循环的片段。问题是减少空间变量

for i <- 0..(row-1) do
  for j <- 0..(col-1) do

  if j == 0 do
  IO.write"+"
  end 

 IO.write "--+"
end
IO.puts ""
columns= col+1


for columns <- 1..columns do
if columns == 1 do
IO.write "|"
end

if spaces < 10 do
IO.write " "
IO.write spaces
IO.write "|"

end

end
spaces = spaces - 1 <- This won't decrement after it goes through the forloop again!
end

end

我需要在Elixir中制作一个输出类似内容的棋盘游戏。

+---+---+---+
| 12| 11| 10|
|B  |   |   |
+---+---+---+
|  7|  8|  9|
| a |  S| e |
+---+---+---+
|  6|  5|  4|
| e |  L|Ad |
+---+---+---+
|  1|  2|  3|
|   |   |   |
+---+---+---+

我已经在java上使用以下代码在另一个for循环中使用for循环来完成它，但这在elixir上是不可能的。有什么想法如何处理这个？谢谢。

编辑：如果有人想看我的java代码，这里就是。

public class math {
static int col = 10;
static int row = 10;
static String top= "---+";
static String side= "|";
static int spaces=col*row;
static int columns; 
static int dash;
static String player="A";
public static void main(String args[]){

    for ( int i=0; i < row; i++ ){
        for ( int j=0; j < col; j++ ){
            if ( j==0) System.out.print("+");

            System.out.print(top);


        }

        System.out.print("\n");
        columns=col+1;

        while( columns > 1){
        if(columns == col+1){
            System.out.print("|");
        }
        if( spaces < 10){
        System.out.print("  "+spaces+"|");}
        else if (spaces <100){
            System.out.print(" "+spaces+"|");
        }
        else{
            System.out.print(""+spaces+"|");
        }
        spaces--;
        columns--;}


        System.out.print("\n");
        columns=col+1;
        while(columns >1){
            if (columns == col +1) {System.out.print("|");}
        System.out.print("   |");
        columns--;}
        System.out.print("\n");
        if( i == row-1){
            int botside = col;
            while(botside !=0){
                if(botside == col){
                    System.out.print("+");
                }
            System.out.print(top);
            botside--;}
            }
            }

            }

Answer 1

你可以使用for special form列表理解来实现你需要的东西：

for i <- 0..(row-1) do
  for j <- 0..(col-1) do
     # Rest of the code
  end
end

Answer 2

以下是我的解决方案 - 基于您填写数据的电路板模板。

defmodule Main do

def main(  ) do

 data = 
 [
   "B  ", "   ",  "   ",
   " a ", "  S",  " e ",
   " e ", "  L",  "Ad ",
   "   ", "   ",  "   ", 
   "" #required terminal
 ]

IO.puts print_board( data )

end

defp print_board( data ) do

board = """
+---+---+---+
| 12| 11| 10|
|   |   |   |
+---+---+---+
|  7|  8|  9|
|   |   |   |
+---+---+---+
|  6|  5|  4|
|   |   |   |
+---+---+---+
|  1|  2|  3|
|   |   |   |
+---+---+---+
"""

String.split( board,"   ")  # Splits board string into a list of strings
 |>  Enum.zip(  data )  # interleaves with data - as list of tuples
 |> Enum.map( fn {a,b} -> a <> b end )  # maps tuples back to merge the list.
end

end

我的测试表明，当您运行Main.main

时，它会产生您所需的结果

不适用于长生不老药的循环。如何制作电路板？

2 个答案: