在VB中打开Wordpad和特定文件

Question

我正在尝试在VB中打开Wordpad和一个特定文件。

我无法弄清楚如何走上正确的道路。如果文件路径中没有空格（错误图像），则它可以工作。

正确的测试路径 C：\ Users \ James \ Documents \ Visual Studio 2015 \ Projects \ DSAinstaller \ DSAinstaller \ bin \ Debug \ Dragon

Private Sub Button2_Click(sender As Object, e As EventArgs) Handles Button2.Click
    If Me.ListBox1.SelectedIndex >= 0 Then
        Dim curItem As String = ListBox1.SelectedItem.ToString()
        Dim OpenFile As String = " " & Application.StartupPath & "\" & curItem & "\Inst.rtf"
        'Shell("C:\Windows\write.exe" & " " & Application.StartupPath & "\" & curItem & "\Inst.rtf")
        Shell("C:\Windows\write.exe" & OpenFile)
        'MsgBox(OpenFile)
    Else
        MsgBox("Please select a program first")
    End If

感谢

Answer 1

如果路径包含空格，则需要在路径中添加引号：

Dim OpenFile As String = " """ & Application.StartupPath & "\" & curItem & "\Inst.rtf"""

Answer 2

请考虑使用Path.Combine()和Process.Start()：

Dim OpenFile As String = Chr(34) & Path.Combine(Application.StartupPath, curItem, "Inst.rtf") & Chr(34)
Process.Start("c:\windows\write.exe", OpenFile)

Shell（）和MsgBox（）是遗留函数，通常不应在VB.Net中使用。