Question

我正在关注Build a console app that connects to CRM guide，当我尝试运行它时，会在NullReferenceException上抛出SaveChanges()。（参见帖子底部的编辑内容）

以下是代码：

using System;
using System.Linq;
using Xrm;
using Microsoft.Xrm.Client;

namespace CRM_Console_Application
{
    class Program
    {
        static void Main(string[] args)
        {

            var xrm = new XrmServiceContext(new Microsoft.Xrm.Client.Services.OrganizationService(new CrmConnection("Xrm")));

            var allisonBrown = new Contact
            {
                FirstName = "Allison",
                LastName = "Brown",
                Address1_Line1 = "23 Market St.",
                Address1_City = "Sammamish",
                Address1_StateOrProvince = "MT",
                Address1_PostalCode = "99999",
                Telephone1 = "12345678",
                EMailAddress1 = "allison.brown@example.com"
            };

            xrm.AddObject(allisonBrown);
            xrm.SaveChanges(); //Here is where it throws an Exception
            WriteExampleContacts(xrm);
            Console.WriteLine("Press any key to exit.");
            Console.ReadKey();
        }

        private static void WriteExampleContacts(XrmServiceContext xrm)
        {
            var exampleContacts = xrm.ContactSet.Where(contact => contact.EMailAddress1.EndsWith("@example.com"));
            foreach (var contact in exampleContacts)
                Console.WriteLine(contact.FullName);
        }
    }
}

另外，我使用的是由CRM SDK中的CrmSvcUtil工具生成的Xrm.cs文件和App.config，如下所示。

<!--App.config-->
<?xml version="1.0" encoding="utf-8" ?>
<configuration>
  <configSections>
    <section name="microsoft.xrm.client" type="Microsoft.Xrm.Client.Configuration.CrmSection, Microsoft.Xrm.Client"/>
  </configSections>
  <connectionStrings>
    <add name="Xrm" connectionString="Server=http://[MyCompanyName].crm.dynamics.com; Username=[MyUsername]; Password=[MyPassword]"/>
  </connectionStrings>
  <microsoft.xrm.client>
    <contexts default="Xrm">
      <add name="Xrm" type="Xrm.XrmServiceContext, Xrm" connectionStringName="Xrm"/>
    </contexts>
  </microsoft.xrm.client>
    <startup> 
        <supportedRuntime version="v4.0" sku=".NETFramework,Version=v4.5.2" />
    </startup>
</configuration>

但我得到了这个错误，似乎无法弄明白为什么。此外，我尝试使用Microsoft的源代码，它返回相同的错误：

处理此请求时出错。 System.NullReferenceException：未将对象引用设置为对象的实例。在Microsoft.Xrm.Sdk.Client.ProxyTypesBehavior.System.ServiceModel.Description.IEndpointBehavior.ApplyClientBehavior（ServiceEndpoint serviceEndpoint，ClientRuntime behavior）在Microsoft.Xrm.Client.Services.OrganizationService.CreateServiceConfiguration（CrmConnection连接）在Microsoft.Xrm.Client.Services.OrganizationService.GetServiceConfiguration（CrmConnection连接）在Microsoft.Xrm.Client.Services.OrganizationService.ToOrganizationServiceProxy（CrmConnection连接）在Microsoft.Xrm.Client.Services.OrganizationService.ToOrganizationService（CrmConnection连接）在Microsoft.Xrm.Client.Services.OrganizationService。＆lt;＆gt; c__DisplayClass2。＆lt; .ctor＆gt; b__0（）在System.Lazy 1.CreateValue() at System.Lazy 1.LazyInitValue（）在System.Lazy 1.get_Value() at Microsoft.Xrm.Client.Services.OrganizationService.InnerOrganizationService.UsingService[TResult](Func 2行动）在Microsoft.Xrm.Client.Services.OrganizationService.Execute（OrganizationRequest request）在Microsoft.Xrm.Sdk.Client.OrganizationServiceContext.Execute（OrganizationRequest request）在Microsoft.Xrm.Sdk.Client.OrganizationServiceContext.SaveChange（OrganizationRequest请求，IList`1结果）

我错过了什么？有什么我做错了吗？

提前致谢。

编辑：不，“重复”链接没有帮助，因为我无法调试XrmServiceContext.SaveChanges()为了获取缺失/空对象所做的事情。

EDIT2：

我修改了我的控制台应用程序（用于连接测试），现在它返回必须填充凭据，但登录信息已经存在。如果我去，也会发生同样的事情

IServiceManagement<IOrganizationService> orgServiceManagement = ServiceConfigurationFactory.CreateManagement<IOrganizationSe‌rvice>(new Uri(url)); 
Sdk.Client.AuthenticationCredentials credentials = new Sdk.Client.AuthenticationCredentials(); 
credentials.ClientCredentials.UserName.UserName = "MyUsername"; 
credentials.ClientCredentials.UserName.Password = "MyPassword"; 
orgServiceManagement.Authenticate(credentials);

尝试在连接到CRM的控制台应用程序上保存ServiceContext的更改时，为什么会出现NullReferenceException？

0 个答案: