Question

这是我的数组的结果

df['hour'] = df.Time.str.split(":").str[0]
df['minute'] = df.Time.str.split(":").str[1]
print (df)
       Time hour minute
0  10:23:00   10     23
1  11:23:00   11     23

我需要使用exp的其他值来从这个数组中获取一些值。如果我在两个单独的数组中有第四个索引的值。

Array
(
[1] => Array
    (
        [0] => ABC
        [1] => abc
        [2] => rodriguez
        [3] => Barkleys, 15 NO.
        [4] => A
        [5] => 1234567890
        [6] => 
        [7] => YES
        [8] => a
    )

[2] => Array
    (
        [0] => DEF
        [1] => def
        [2] => DAM
        [3] => Barkleys, 15 NO.
        [4] => A
        [5] => 1234567891
        [6] => 
        [7] => YES
        [8] => b
    )

[3] => Array
    (
        [0] => GHI
        [1] => ghi
        [2] => TEG
        [3] => Street4
        [4] => B
        [5] => 1234567892
        [6] => YES
        [7] => 
        [8] => c
    )

[4] => Array
    (
        [0] => JKL
        [1] => jkl
        [2] => CHA
        [3] => Street4
        [4] => B
        [5] => 1234567893
        [6] => YES
        [7] => 
        [8] => d
    )


   )

现在我需要使用以上两个数组值

获取两个单独数组中第二个索引的值

array ( 
        [0] =>  A 
        [1] =>  A
      )
array (
        [0] =>  B 
        [1] =>  B
      )

我该怎么做才能提出解决方案。

Answer 1

您可以尝试这样做：

<?php

$firstArray = array();
foreach($bigArray as $key => $array) {
    $value = $array[4]; //fetch the 4th indice
    if(! isset($firstArray[$value])) {
        $firstArray[$value] = array();
    }

    $firstArray[$value][$key] = $value;
}

$secondArray = array();
foreach($firstArray as $name => $array) {
    foreach($array as $key => $info) {
        $value = $bigArray[$key][2]; //fetch the 2nd indice

        if(! isset($secondArray[$value])) {
            $secondArray[$value] = array();
        }

        $secondArray[$value][$key] = $value;
    }
}

从数组中获取值取决于其他值PHP

1 个答案: