Question

我遇到一个问题，我无法使 WEEK（日期，模式）功能正常工作。

我有一个SQL，我按年度分组总和，然后按周分组：

SELECT SUM(o.total) as total_org, SUM(o.total_eur) as total_eur, 
WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)) as period, YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)) as smallerperiod, `s`.`domain`
FROM `orders` `o`
JOIN `shops` `s` ON `o`.`domain_id` = `s`.`id`
WHERE `o`.`domain_id` = '5'
GROUP BY YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)), WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR))
ORDER BY `smallerperiod` ASC, `period` ASC

哪个完全符合我的要求，除了从0开始的周数。我发现对我来说效果最好的模式是3号，所以我尝试将我的SQL更改为：

SELECT SUM(o.total) as total_org, SUM(o.total_eur) as total_eur, 
WEEK('DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)', 3) as period, YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)) as smallerperiod, `s`.`domain`
FROM `orders` `o`
JOIN `shops` `s` ON `o`.`domain_id` = `s`.`id`
WHERE `o`.`domain_id` = '5'
GROUP BY YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)), WEEK('DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)', 3))
ORDER BY `smallerperiod` ASC, `period` ASC

然而它只是给了我错误

您的SQL语法有错误;查看与MariaDB服务器版本对应的手册，以获取正确的语法靠近＆＃39;）ORDER BY smallerperiod ASC，period ASC

编辑：我试图让它在没有单引号的情况下工作：

SELECT SUM(o.total) as total_org, SUM(o.total_eur) as total_eur, 
WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR), 3) as period, YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)) as smallerperiod, `s`.`domain`
FROM `orders` `o`
JOIN `shops` `s` ON `o`.`domain_id` = `s`.`id`
WHERE `o`.`domain_id` = '5'
GROUP BY YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)), WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR), 3))
ORDER BY `smallerperiod` ASC, `period` ASC

但是，它会返回相同的错误

Answer 1

您必须删除单引号arround 'DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)'，因为您要调用函数而不是将其用作字符串。

你得到了theeroor，因为你在这里有一个额外的括号：HOUR)', 3))

所以查询必须是：

SELECT SUM(o.total) as total_org, SUM(o.total_eur) as total_eur, 
WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR), 3) as period, YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)) as smallerperiod, `s`.`domain`
FROM `orders` `o`
JOIN `shops` `s` ON `o`.`domain_id` = `s`.`id`
WHERE `o`.`domain_id` = '5'
GROUP BY YEAR(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR)), WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR), 3)
ORDER BY `smallerperiod` ASC, `period` ASC

Answer 2

你只需要在getContext()之后移除最后一个括号。否则，我已经尝试了相同的完美性。您也可以尝试下面的代码。

WEEK(DATE_ADD(o.date_created_utc, INTERVAL 0 HOUR), 3))

在模式

2 个答案: