Question

我的数据库中有1个品牌和2个分支，我正在获取每个分支的销售数据。

public function getCurrentSales($brandid){
$branches = DB::table('gc_branch')->where('BRAND_ID', $brandid)
                                  ->select('BRANCHID', 'BRANCHNAME')
                                  ->get(); 

for ($i=0; $i<count($branches);$i++){
$mtdnetsales= DB::table('st_sales')
//query
->select(DB::raw('sum(AMOUNT) as TOT')->get();

$ytdnetsales= DB::table('st_sales')
//query
->select(DB::raw('sum(AMOUNT) as TOT')->get();


$netsalesdata=[['BRANCHID' => $branches[$i]->BRANCHID, 'BRANCHNAME' =>branches[$i]->BRANCHNAME, 'MTDNETSALES' =>$mtdnetsales[0]->TOT, 'YTDNETSALES' =>$ytdnetsales[0]->TOT]];

}//end for

return $netsalesdata;

我的问题是：

如果我将返回$netsalesdata放入for循环中，我只获得第一个原始数据（仅限1个分支）
如果我把它放在循环之外，我得到最后一行（仅第二个分支），而我的数据库有2个分支

Answer 1

将您的netstellar更改为此（并将其保留在for循环中）：

$netsalesdata[$i]=[['BRANCHID' => $branches[$i]->BRANCHID, 'BRANCHNAME' =>branches[$i]->BRANCHNAME, 'MTDNETSALES' =>$mtdnetsales[0]->TOT, 'YTDNETSALES' =>$ytdnetsales[0]->TOT]];

并返回：

return $netsalesdata[];

Answer 2

public function getCurrentSales($brandid) {
    $branches = DB::table('gc_branch')->where('BRAND_ID', $brandid)
                  ->select('BRANCHID', 'BRANCHNAME')->get(); 

    for ($i=0; $i<count($branches);$i++){
        $mtdnetsales= DB::table('st_sales')
               ->select(DB::raw('sum(AMOUNT) as TOT')->get();

        $ytdnetsales= DB::table('st_sales')
               ->select(DB::raw('sum(AMOUNT) as TOT')->get();

        $netsalesdata[] =[
            'BRANCHID' => $branches[$i]->BRANCHID,
            'BRANCHNAME' =>branches[$i]->BRANCHNAME,
            'MTDNETSALES' =>$mtdnetsales[0]->TOT,
            'YTDNETSALES' =>$ytdnetsales[0]->TOT];

    }//end for

   // get size of the array
   $records = count($netsalesdata);
   // To get last record
   print_r($netsalesdata[$records -1]);
}

Answer 3

使用array_push函数追加新变量：

public function getCurrentSales($brandid){
    $netsalesdata= [];
    $branches = DB::table('gc_branch')->where('BRAND_ID', $brandid)
                                      ->select('BRANCHID', 'BRANCHNAME')
                                      ->get(); 

    for ($i=0; $i<count($branches);$i++){
        $mtdnetsales= DB::table('st_sales')
        //query
        ->select(DB::raw('sum(AMOUNT) as TOT')->get();

        $ytdnetsales= DB::table('st_sales')
        //query
        ->select(DB::raw('sum(AMOUNT) as TOT')->get();


        array_push($netsalesdata, ['BRANCHID' => $branches[$i]->BRANCHID, 'BRANCHNAME' =>branches[$i]->BRANCHNAME, 'MTDNETSALES' =>$mtdnetsales[0]->TOT, 'YTDNETSALES' =>$ytdnetsales[0]->TOT]);

     }//end for

     return $netsalesdata;
}

Laravel for循环返回数组中的数据

3 个答案: